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astra-53 [7]
3 years ago
8

The transfer of energy that occurs when a force is applied over a distance is

Physics
1 answer:
astra-53 [7]3 years ago
3 0
The transfer of energy that occurs when a force is applied over a distance is WORK.
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Franklin needs to ship a box with FedEx. In order to calculate his shipping costs, he needs to measure the mass of the package.
balandron [24]

Answer:

meter

Explanation:

please mark as brainlist answer

8 0
3 years ago
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Two paths lead to the top of a big hill. One is steep and direct, while the other is twice as long but less steep. How much more
umka2103 [35]

Answer:

None.

Explanation:

  • Gravitational potential energy, depends only of the mass on which the gravity is doing work, and the displacement produced by this force.
  • As displacement depends only on the final and initial positions (in this case, the height of the hill), if we choose as our zero reference level the bottom of the hill, the change in gravitational potential energy will be as follows:

       \Delta U = U_{f} -U_{0} = m*g*h - 0  = m*g*h

  • As we can see, the only value of distance involved is the height of the hill , so it is independent of the distance travelled.
6 0
3 years ago
What's an easy way to create an interference pattern of waves?
igor_vitrenko [27]

Answer:

B

Explanation:

5 0
3 years ago
A railroad car of mass 2.50*10^4 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railroa
NemiM [27]

Answer:

(a) 2.5 m/s

(b) 37.5 KJ

Explanation:

(a)

From the law of conservation of momentum, Initial momentum=Final momentum

mV_1+3mV_2=(m+3m)V_f=4mV_f

V_1+3V_2=4V_f and making V_f the subject then

V_f=\frac {V_1+3V_2}{4} and since V_1 is initial velocity of car, value given as 4 m/s, V_2 is the initial velocity of the three cars stuck together, value given as 2 m/s and v_f is the final velocity which is unknown. By substitution

V_f=\frac {4+(3\times2)}{4}=2.5 m/s

(b)

Initial kinetic energy is given by

\frac {mV_1^{2}}{2}+\frac {3mV_2^{2}}{2}=\frac {m(V_1^{2}+3V_2^{2}}{2}=\frac {2.5\times 10^{4}(4^{2}+3(2^{2}))}{2}=350\times10^{3} J= 350 KJ

Final kinetic energy is given by

\frac {4mV_f^{2}}{2}=\frac {4\times 2.5\times 10^{4}\times 2.5^{2}}{2}=312.5\times 10^{3} J=312.5 KJ

The energy lost is given by subtracting the final kinetic energy from the initial kinetic energy hence

Energy lost=350-312.5=37.5 KJ

6 0
3 years ago
Read 2 more answers
If a ball has a velocity of 18 m/s, how far does it travel in 15 seconds
Stolb23 [73]

Answer:

The answer is

<h2>270 m</h2>

Explanation:

To find the distance when given the velocity and time we use the formula

<h3>distance = velocity × time</h3>

From the question

velocity of the ball = 18 m/s

time = 15 s

So the distance is

distance = 18 × 15

We have the final answer as

<h3>270 m</h3>

Hope this helps you

7 0
3 years ago
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