Answer:
(BH3 follows the octet rule by dimerizing, as Hadi Kurniawan AR pointed out.) For H and He, an "octet" = 2 electrons. Boron does prefer to follow the octet rule, in that it likes to form borate compounds such as NaBH4. It also is happy to form compounds with elements with lone pairs.
Newton’s second law of motion is a dot product of mass and acceleration, if you remove the table from, under the book, gravity will act on the book and pull it downwards to the centre of the earth
Newton's Second law of motion states that "<em>the </em><em>acceleration</em><em> of an object depends upon </em><em>two</em><em> </em><em>variables</em><em> – the net force acting on the object and the mass of the object.</em>"
In our case the mass of the book and the force of gravity
Learn more about Newton's Laws of motion:
brainly.com/question/10454047
This problem has two parts; the first one asking for the concentration of NaBr given both its mass and volume and the second one asking for its volume given both mass and concentration. The answers turn out to be 0.158 M and 211 mL.
<h3>Molarity</h3>
In chemistry, the use of units of concentration depends on both the substances to analyze and their amounts. In such a way, for molarity, one needs the following relationship between the moles of solute and volume of solution:
Thus, for the first part of the problem we first calculate the moles in 2.60 g of NaBr via its molar mass:
Next, we convert the 160. mL to L by dividing by 1000 in order to obtain 0.160 L to subsequently calculate the molarity:
Next, since the moles remain the same and for the second part we are asked for the volume given the concentration, one can solve for the volume so as to obtain:
That in milliliters turns out to be:
Learn more about molarity: brainly.com/question/10053901
<span>In commonly table salt is sodium chloride. When table salt is dissolved in water, the solution conducts electricity because sodium chloride is made up of ions, it is called an ionic substance.</span>
Answer:
True
Explanation:
Aromatic compounds undergo substitution rather than addition reactions because the aromatic structure is maintained.
Electrophilic aromatic substitution begins with attack of the electrophile on the aromatic ring to yield a delocalized intermediate called the arenium intermediate. Loss of hydrogen from this intermediate yields the final product.
