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kondaur [170]
3 years ago
9

A long distance phone company charges $0.05 per minute, plus a monthly charge of $5. Another long distance phone company charges

$0.09 per minute with no monthly charge. For how many minutes per month is the cost the same?
Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

Step-by-step explanation:

One approach to this type of word problem is to list the information you are given:

Step 1:

$19.95 = basic monthly charge

$0.05 = per minute charge$23.74 = total monthly billx = the number of minutes used

Step 2:

Next, put these things into an algebraic expression.

Total monthly bill = basic monthly charge + (per minute charge) * (number of minutes used)

Step 3:

Now, plug in the numbers for your first step and solve.

$23.74 = $19.95 + $0.05x

-19.95      -19.95

$3.79 = $0.05x

divide each side by 0.05 to find x

You could also rewrite the problem at step 2. It just depends if you like working with numbers (algebra, variables, etc.) or thinking about the problem in words (more a verbal style of learning).

Number of minutes used = cost for minutes / per minute charge

Number of minutes used = (Total monthly charge - basic monthly charge)  / per minute charge

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