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Anon25 [30]
2 years ago
13

Solve each of the given equations and show your work. If the equation has no solution or infinitely many solutions, circle that

instead of writing an answer.
6. 2(x+3.5)-x=-3(6-2x) ANSWER: __________
no solution infinitely many solutions






7. -17+2(1+3x)=x-5(3-x) ANSWER: __________
no solution
infinitely many solutions







8. -2(x+4)+9x=4+7x ANSWER: __________
no solution
infinitely many solutions
Mathematics
2 answers:
erastova [34]2 years ago
6 0
-3.544
2(x+3.5)-x-3(6-2x)
bezimeni [28]2 years ago
3 0

Answer:

6.) -3.544

Step-by-step explanation:

6.2(x+3.5)-x =6.2x+21.7 -x =6.2x-x+21.7 =5.2x+21.7

-3(6-2x) =-18(+-)6x =-18-6x

5.2x +6x=-18-21.7

11.2x=-39.7

x=-39.7÷11.2

x=3.544

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What is the first step in writing f(x) = 6x2 + 5 – 42x in vertex form?
Marina CMI [18]
The first step to getting this in vertex form would be to put this in proper standard form. This is so that you can split the middle term which is a step of completing the square. 
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What is the answer to the expression “ 13! “
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5 0
3 years ago
Y=x2-2x-5<br> Change to vertex form
MaRussiya [10]

The vertex form is y=(x-1)^{2} -6

Step-by-step explanation:

The given equation y=x^{2} -2x-5 is a parabola. The vertex of the parabola is of the form y=ax^{2} +bx+c  

The parameters of the parabola are a=1, b=-2 and c=-5

The vertex of the x-coordinate is given by x=\frac{-b}{2a}

Thus, substituting the values of a and b in x=\frac{-b}{2a}, we get,

\begin{aligned}x &=\frac{-(-2)}{2(1)} \\&=\frac{2}{2} \\x &=1\end{aligned}

Now, substituting x=1 in y=x^{2} -2x-5, we get,

\begin{aligned}y &=1^{2}-2(1)-5 \\&=1-2-5 \\y &=-6\end{aligned}

Thus, the vertex is (1,-6)

The equation of parabola to be in vertex form is y=a(x-h)^{2} +k

where a is the coefficient of x^{2}, h is vertex of the x-coordinate and k is the vertex of the y-coordinate.

Hence, a=1, h=1 and k=-6

Thus, substituting the values in the equation of the vertex form,

y=1(x-1)^{2} -6\\y=(x-1)^{2} -6

Hence, the vertex form is y=(x-1)^{2} -6

8 0
3 years ago
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