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Anika [276]
3 years ago
12

Solve the formula for V in terms of d and m

Mathematics
1 answer:
Phantasy [73]3 years ago
5 0

Step-by-step explanation:

d = \frac{m}{V}

V \times d = m

V = \frac{m}{d}

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Select the statement that is FALSE. The range is never greater than the greatest value of a data set. The interquartile range is
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Answer:

The interquartile range is the difference between the highest and lowest values in the middle of a data set.

Step-by-step explanation:

The range is the difference between the maximum and minimum value, hence, it cannot be greater than the maximum value, which is the greatest value in a dataset, the highest value a range could have being equal to the maximum value when the minimum vlaue of the dataset is equal to 0.

The mean is the average value of a dataset, hence, it cannot be greater than the maximum value.

The interquartile range is the middle 50% or half of a dataset and not the difference between the highest and lowest middle values in the middle. It is obtained by taking the difference of the upper and lower QUARTILE.

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How do you solve this
brilliants [131]
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Solve the system of linear equations by substitution.<br> 2x-y=3<br> x+5y=14
adoni [48]
Let 2x – y = 3 ——— equation 1

Let x + 5y = 14 ——— equation 2

Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3

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6y = 14 – 3/2

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Help me solve the binary operations please ​
son4ous [18]

Answer:

  • 3*2=\sf{\pink{\dfrac{4}{5}}}

Step-by-step explanation:

<u>Given</u><u> </u><u>that</u><u>,</u><u> </u>

x*y=\dfrac{(2x-y)}{(x+y}

<h3><u>SO</u><u>,</u><u> </u></h3>

3*2=

\dfrac{2(3)-2}{3+2}\\\\\dfrac{6-2}{5}\\\\\dfrac{4}{5}

<u>Therefore</u><u>:</u><u>-</u>

\therefore  {3*2}=\dfrac{4}{5}

6 0
2 years ago
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