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3 years ago

Write the complete electron configuration for Chlorine.

Physics

1 answer:

In-s [12.5K]3 years ago

7 0

Answer: The answer is: [Ne] 3s² 3p⁵

Explanation:

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A 3.0 pF capacitor consists of two parallel plates that have surface charge densities of 1.0 nC/mm2 . If the potential between t

Archy [21]

Answer:

$A=81mm^2$

Explanation:

We know that for a capacitor $Q=CV$ , where Q is the charge of one plate, C the capacitance and V the potential between the plates.

We also know that $Q=\sigma A$ , since $\sigma$ is the surface charge density and A the area of the plate (both equal in our case).

Putting all together:

$A=\frac{CV}{\sigma}$

Which for our values is:

$A=\frac{(3\times10^{-12}F)(27\times10^3V)}{1\times10^{-9}C/mm^2}=81mm^2$

Where we notice that the S.I. units combination FV/C must not have units (we can verify it directly from their definitions or we notice that $mm^2$ is enough to describe an area).

8 0

3 years ago

6. A car accelerates from rest to 5m/s in 20 s. The force from the engine is 2000N. The force of air resistance and friction act

otez555 [7]

Answer:

net force= 2000-1000=1000

a=v-u/t=5/20=1/4

m=?

m=f/a

=1000÷1/4=4000kg

4 0

3 years ago

Find the required answer to the following by substituting the numbers. (Bonus points for knowing the units). PLEASE ANSWER

Alex73 [517]

Answer:

a) F=ma

F=13.2×10

F=132

b) I=P/V

I=75/15

I=5

4 0

3 years ago

The specific heat of soil is 0.20 kcal/kg*C and the specific heat of water is 1.00 kcal/kg*C. This means that if 1 kg of soil an

stiv31 [10]

Answer: The soil will be $4\°C$ warmer than the water.

Explanation:

The heat (thermal energy) absorbed can be found using the following equation:

$Q=m.C.\Delta T$

Where:

$Q$ is the heat

$m$ is the mass of the element

$C$ is the specific heat capacity of the material.

$\Delta T$ is the variation in temperature

In the case of soil we have:

$Q_{soil}=m_{soil}.C_{soil}.\Delta T_{soil}$ (1)

Where:

$Q_{soil}=1 kcal$

$m_{soil}=1 kg$

$C_{soil}=0.2 kcal/kg \°C$

$\Delta T_{soil}$

In the case of water we have:

$Q_{water}=m_{water}.C_{water}.\Delta T_{water}$ (2)

Where:

$Q_{water}=1 kcal$

$m_{water}=1 kg$

$C_{water}=1 kcal/kg \°C$

$\Delta T_{water}$

Isolating $\Delta T$ from both equations:

$\Delta T_{soil}=\frac{Q_{soil}}{m_{soil}.C_{soil}}$ (3)

$\Delta T_{soil}=\frac{1 kcal}{1 kg(0.2 kcal/kg \°C)}$

$\Delta T_{soil}=5\°C$ (4)

$\Delta T_{water}=\frac{Q_{water}}{m_{water}.C_{water}}$ (5)

$\Delta T_{water}=\frac{1 kcal}{1 kg(1 kcal/kg \°C)}$

$\Delta T_{water}=1\°C$ (6)

Comparing (4) and (6) we can find the soil will be $4\°C$ warmer than the water.

8 0

4 years ago

Mostly question three, but I'm not sure how to work out the speed. Thank you!

telo118 [61]

The speed of sound follows the same rules, just like any other speed, if the acceleration is zero.

distance = speed * time

distance = 2m
speed = 333m/s

Solve for time t.

8 0

3 years ago

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