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ehidna [41]
2 years ago
7

What mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

Chemistry
1 answer:
nikitadnepr [17]2 years ago
5 0

The mass of water produced by the reaction of the 23 g of SiO_2  is 13.8 g.

The given chemical reaction;

4Hf (g)  \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l)

In the given compound above, we can deduce the following;

  • molecular mass of SiO_2 = 28 + (2 x 16) = 60 g
  • molecular mass of 2H_2O = 2(18) = 36 g

60 g of SiO_2  --------- 36 g of water

23 g of SiO_2  ------------- ? of water

mass \ of \ water = \frac{23 \times 36}{60} = 13.8 \ g \ of \ water

Thus, the mass of water produced by the reaction of the 23 g of SiO_2  is 13.8 g.

  • <em>"Your question is not complete, it seems to be missing the following information";</em>

In the reaction of the given compound, 4Hf (g)  \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l), what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

Learn more here:brainly.com/question/13644576

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Mixtures of benzene and cyclohexane exhibit ideal behavior. A solution was created containing 1.5 moles of liquid benzene and 2.
goblinko [34]

Answer:

Vapour pressure of cyclohexane at 50°C is 490torr

Vapour pressure of benzene at 50°C is 90torr

Explanation:

Using Raoult's law, pressure of a solution is defined by the sum of the product sbetween mole fraction of both solvents and pressure of pure solvents.

P_{solution} = X_{A}P^0_{A}+X_{B}P^0_{B}

In the first solution:

X_{cyclohexane}=\frac{2.5mol}{2.5mol+1.5mol} =0.625

X_{benzene}=\frac{1.5mol}{2.5mol+1.5mol} =0.375

340torr = 0.625P^0_{A}+0.375P^0_{B} <em>(1)</em>

For the second equation:

X_{cyclohexane}=\frac{3.5mol}{3.5mol+1.5mol} =0.700

X_{benzene}=\frac{1.5mol}{3.5mol+1.5mol} =0.300

370torr = 0.700P^0_{A}+0.300P^0_{B}<em>(2)</em>

Replacing (2) in (1):

340torr = 0.625P^0_{A}+0.375(1233.3-2.333P^0_{A})

340torr = 0.625P^0_{A}+462.5-0.875P^0_{A}

-122.5torr = -0.250P°A

P^0_{A} = 490 torr

<em>Vapour pressure of cyclohexane at 50°C is 490torr</em>

And for benzene:

370torr = 0.700*490torr+0.300P^0_{B}

P^0_{B}=90torr

<em>Vapour pressure of benzene at 50°C is 90torr</em>

3 0
2 years ago
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