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ehidna [41]
2 years ago
7

What mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

Chemistry
1 answer:
nikitadnepr [17]2 years ago
5 0

The mass of water produced by the reaction of the 23 g of SiO_2  is 13.8 g.

The given chemical reaction;

4Hf (g)  \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l)

In the given compound above, we can deduce the following;

  • molecular mass of SiO_2 = 28 + (2 x 16) = 60 g
  • molecular mass of 2H_2O = 2(18) = 36 g

60 g of SiO_2  --------- 36 g of water

23 g of SiO_2  ------------- ? of water

mass \ of \ water = \frac{23 \times 36}{60} = 13.8 \ g \ of \ water

Thus, the mass of water produced by the reaction of the 23 g of SiO_2  is 13.8 g.

  • <em>"Your question is not complete, it seems to be missing the following information";</em>

In the reaction of the given compound, 4Hf (g)  \ + \ SiO_2 (s) \ --> \ SiF_4(g) \ + \ 2H_2O(l), what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?

Learn more here:brainly.com/question/13644576

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For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox
ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: m_{N2}=10.682 g N_2

2) Limiting reagent: NO

3) Ammount of excess reagent: m_{N2}=4.274 g

Explanation:

<u>The reaction </u>

2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)

Moles of nitrogen monoxide

Molecular weight: M_{NO}=30 g/mol

n_{NO}=\frac{m_{NO}}{M_{NO}}

n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol

Moles of hydrogen

Molecular weight: M_{H2}=2 g/mol

n_{H2}=\frac{m_{H2}}{M_{H2}}

n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}

m_{N2}=10.682 g N_2

2) <u>Limiting reagent</u>: NO

3) <u>Ammount of excess reagent</u>:

m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}

m_{N2}=4.274 g

8 0
3 years ago
What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

8 0
3 years ago
Compute 6.28×1013+7.30×1011.
Simora [160]
6.28×1013+7.30×1011 this =13741.94
6 0
4 years ago
With which group would group 18 most likely bond
Mice21 [21]

Answer:

The noble gases (Group 18) are located in the right of the periodic table and were previously referred to as the "inert gases" due to the fact that their filled valence shells (octets) make them extremely nonreactivE

Explanation:

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3 years ago
If a tube is 2.2 meters in length, how long is the the tube in feet ?​
trapecia [35]

Answer:

7.22 feet long

Explanation:

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2.2 × 3.28084 = 7.2<u>1</u>785

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I hope this is helpful :)

3 0
3 years ago
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