Answer:
Discharge Rate = 0.2 cubic meters per second
Explanation:
Torricelli's Law is derived from Bernoulli's equation and simply states that the speed of the efflux in a Torricelli apparatus (shown below) is directly proportional to and affected only by the height of the fluid above it.
V = √2g(10-2)
Putting value of g = 9.8 we get:
V = 12.52 m/s
Discharge rate = Q = A × V
= 1.60/100 × 12.52
= 0.2 cubic meter per second
Best Regards!
Answer:
Explanation:
angular acceleration α = 6.61 / 8.97 = .737 rad / s²
moment of inertia = 1/3 m L²
= 1/3 x 1.13 x .899²
= .3045 kg m²
torque applied = moment of inertia x angular acceleration
= .737 x .3045 = .2244
If be the force
Torque
= F x .899 = .2244
F = .25 N ,
Answer:
C. 0.2 Hertz
Explanation:
The frequency of a spring is equal to the reciprocal of the period:
where
f is the frequency
T is the period
For the spring in this problem,
T = 5 s
therefore, the frequency is
use the formula: v^2=(3kT)/m
Where:
<em>v is the velocity of a molecule</em>
<em>k is the Boltzmann constant (1.38064852e-23 J/K)</em>
<em>T is the temperature of the molecule in the air</em>
<em>m is the mass of the molecule</em>
For an H2 molecule at 20.0°C (293 K):
v^2 = 3 × 1.38e-23 J/K × 293 K / (2.00 u × 1.66e-27 kg/u)
v^2 = 3.65e+6 m^2/s^2
v = 1.91e+3 m/s
For an O2 molecule at same temp.:
v^2 = 3 × 1.38e-23 J/K × 293 K / (32.00 u × 1.66e-27 kg/u)
v^2 = 2.28e+5 m^2/s^2
v = 478 m/s
Therefore, the ratio of H2:O2 velocities is:
1.91e+3 / 478 = 4.00
Energy is always needed to preform anything, and chemical energy is one form of energy. Chemical energy is a part of chemical reactions because it involves teh chemicals.
