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Ksju [112]
3 years ago
5

Outbreak of diseases

Physics
1 answer:
damaskus [11]3 years ago
3 0
Episemic might be it but you need to be more specific!
You might be interested in
NEED A PHYSICS EXPERT TO HELP ME PLS
Brut [27]

Answer:

Discharge Rate = 0.2 cubic meters per second

Explanation:

Torricelli's Law is derived from Bernoulli's equation and simply states that the speed of the efflux in a Torricelli apparatus (shown below) is directly proportional to and affected only by the height of the fluid above it.

V = √2g(10-2)

Putting value of g = 9.8 we get:

V = 12.52 m/s

Discharge rate = Q = A × V

= 1.60/100 × 12.52

= 0.2 cubic meter per second

Best Regards!

5 0
3 years ago
A uniform rod is set up so that it can rotate about an axis at perpendicular to one of its ends. The length and mass of the rod
allsm [11]

Answer:

Explanation:

angular acceleration α = 6.61 / 8.97 = .737 rad / s²

moment of inertia = 1/3  m L²

= 1/3  x 1.13 x .899²

= .3045  kg m²

torque applied = moment of inertia x angular acceleration

= .737 x .3045 = .2244

If be the force

Torque

= F x .899 = .2244

F = .25 N ,

4 0
3 years ago
If the period of a spring is 5 seconds what is the frequency
Scilla [17]

Answer:

C. 0.2 Hertz

Explanation:

The frequency of a spring is equal to the reciprocal of the period:

f=\frac{1}{T}

where

f is the frequency

T is the period

For the spring in this problem,

T = 5 s

therefore, the frequency is

f=\frac{1}{5 s}=0.2 Hz

7 0
4 years ago
The molecular weight of oxygen gas (o2) is 32 while that of hydrogen gas (h2) is 2.
anzhelika [568]

use the formula: v^2=(3kT)/m

Where:

<em>v is the velocity of a molecule</em>

<em>k is the Boltzmann constant (1.38064852e-23 J/K)</em>

<em>T is the temperature of the molecule in the air</em>

<em>m is the mass of the molecule</em>

For an H2 molecule at 20.0°C (293 K):

v^2 = 3 × 1.38e-23 J/K × 293 K / (2.00 u × 1.66e-27 kg/u)

v^2 = 3.65e+6 m^2/s^2

v = 1.91e+3 m/s

For an O2 molecule at same temp.:

v^2 = 3 × 1.38e-23 J/K × 293 K / (32.00 u × 1.66e-27 kg/u)

v^2 = 2.28e+5 m^2/s^2

v = 478 m/s

Therefore, the ratio of H2:O2 velocities is:

1.91e+3 / 478 = 4.00

7 0
3 years ago
Why is chemical energy a part of all chemical reactions?
lana [24]
Energy is always needed to preform anything, and chemical energy is one form of energy. Chemical energy is a part of chemical reactions because it involves teh chemicals. 

5 0
3 years ago
Read 2 more answers
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