Answer:
4 kg of sugar would contain
crystals.
Step-by-step explanation:
Given that 3kg of sugar contains 9 × 10⁸ crystals, let "x" represent the number of sugar crystals 4kg of sugar would contain.
Thus, set up a proportion as follows:
3 kg : 9 × 10⁸ = 4 kg : x

Solve for x. Cross multiply.



Divide both sides by 3


4 kg of sugar would contain
crystals.
The mean is the average value of all data in a set.
Solution:
Given: ABCD is a Rhombus
To Prove: ΔABC≅ΔCDA
Construction: Join AC as diagonal.
Proof: ABCD is Rhombus whose sides are equal and diagonal are perpendicular bisectors. Please see attach figure.
In ΔABC and ΔCDA
AB=CD (Side of same Rhombus)
BC=DA (Side of same Rhombus)
AC=CA (Common Side of both triangle)
Therefore, ΔABC≅ΔCDA by SSS property of congruence.
Hence Proved, ΔABC≅ΔCDA