Answer:
A is correct <em>answer.I </em><em>hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>you</em>
Answer:
decrease i had the same question in 8th grade u must be in ninth
Explanation:
ohh im not sure but i think its A
29.26 gram
Explanation:
No of molecules = no of mole × Avogadro's number
No of molecules = mass in gram/ molar mass × Avogadros number
Mass in gram =No of molecules×molar mass / Avogadros number
Mass in gram = 3.012 ×10^23 × 58.5/6.02×10^23
29.26 gram
Well thats a pretty difficult question, I think the answer might be 4
Answer : The solubility of a gas in water at 1 atm pressure is, 0.4436 g/L
Solution : Given,
Solubility of a gas in water = 1.22 g/L (at 2.75 atm pressure)
At pressure = 1 atm, Solubility of a gas = ?
Now we have to calculate the solubility of a gas.
At 2.75 atm pressure, the solubility of a gas in water = 1.22 g/L
At 1 atm pressure, the solubility of a gas in water = 
Therefore, the solubility of a gas in water at 1 atm pressure is, 0.4436 g/L