Chemical Formula NH3 Element Element 1 Element 2 Element 3 Color 1 Color 2 Color 3

A voltaic cell differs from an electrolytic cell in that in a voltaic cell

Fofino [41]

The answer is A. Voltaic cells couple oxidation and reduction half reactions to produce electromotive force from chemical potential energy. Electrolytic cells do the opposite in that they require electromotive force to store chemical energy.

6 0

4 years ago

Using the following thermochemical data, what is the change in enthalpy for the following reaction?

slavikrds [6]

Answer:

D. -120.9 kJ

Explanation:

According to Hess's law ,the total enthalpy change for a reaction is the sum of all changes regardless of the stages or the steps of the reaction.

$CaO + 2HCl \rightarrow CaCl_{2} + H_{2}O\ (\Delta H = -186\ kJ)$ ....(1)

$CaO + H_{2}O\rightarrow Ca(OH)_{2}\ (\Delta H = - 65 \ kJ)$

(this reaction should be reversed in order to reach the required reaction )

On reversing the reaction the sign of $\Delta H$ get reversed.

(In this case change sign from '-' to'+'. Hence $\Delta H$ = + 65 kJ)

$CaO + 2HCl \rightarrow CaCl_{2} + H_{2}O\ (\Delta H = - 186\ kJ)$ ....(1)

$Ca(OH)_{2} \rightarrow CaO + H_{2}O\ (\Delta H = + 65 kJ )$ ......(2)

Adding equation (1) and (2)

$Ca(OH)_{2} + 2HCl \rightarrow CaCl_{2} + 2H_{2}O[tex][tex]Delta H = - 186 + 65 = - 121\kJ$

$Delta H = - 121\kJ$ (It is nearly equal to -120.9 kJ)

7 0

3 years ago

The half-life of tritium (H-3) is 12.3 years. If 48.0mg of tritium is released from a nuclear power plant during the course of a

Rudiy27

Answer:

The amount left after 49.2 years is 3mg.

Explanation:

Given data:

Half life of tritium = 12.3 years

Total mass pf tritium = 48.0 mg

Mass remain after 49.2 years = ?

Solution:

First of all we will calculate the number of half lives.

Number of half lives = T elapsed/ half life

Number of half lives = 49.2 years /12.3 years

Number of half lives = 4

Now we will calculate the amount left after 49.2 years.

At time zero 48.0 mg

At first half life = 48.0mg/2 = 24 mg

At second half life = 24mg/2 = 12 mg

At 3rd half life = 12 mg/2 = 6 mg

At 4th half life = 6mg/2 = 3mg

The amount left after 49.2 years is 3mg.

6 0

4 years ago

How many grams of calcium chloride will be produced when 29.0 g of calcium carbonate is combined with 15.0 g of hydrochloric aci

horsena [70]

Answer:

22.7 g of CaCl₂ are produced in the reaction

Explanation:

This is the reaction:

CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O

Now, let's determine the limiting reactant.

Let's divide the mass between the molar mass, to find out moles of each reactant.

29 g / 100.08 g/m = 0.289 of carbonate

15 g / 36.45 g/m = 0.411 of acid

1 mol of carbonate must react with 2 moles of acid

0.289 moles of carbonate will react with the double of moles (0.578)

I only have 0.411 of HCl, so the acid is the limiting reactant.

Ratio is 2:1, so I will produce the half of moles, of salt.

0.411 / 2 = 0.205 moles of CaCl₂

Mol . molar mass = mass → 0.205 m . 110.98 g/m = 22.7 g

5 0

4 years ago

Determine the mass of co2 prodeced by burning enough carbon to produce 5 x 10^2 kj

olga55 [171]

Answer:

= 55.7g

Explanation:

12g of carbon burnt to produce 5x10^2KJ

So, 5x10^2KJ(12g/393.5KJ)=15.2g

Then mas of CO2 is 44g

So, 15.2g(12g/44g)=57.7g

7 0

3 years ago

Chemical Formula NH3 Element Element 1 Element 2 Element 3 Color 1 Color 2 Color 3​

Chemical Formula NH3 Element Element 1 Element 2 Element 3 Color 1 Color 2 Color 3