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asambeis [7]
4 years ago
9

I need help with this answer

Chemistry
1 answer:
frez [133]4 years ago
7 0
A
not every expirement has control
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2. How many joules of heat are required to heat 237 g of lithium fluoride (specific heat = 1.56
malfutka [58]
The answer is 24,327.58 joules
8 0
3 years ago
A teacher wants to preform a class room demonstration that illustrates both chemical and physical changes. which would be the be
sp2606 [1]

Answer:

D) burning a candle

Explanation

When burning a candle no new substance is form.

We have both physical and chemical change occuring.

Physical part: Melting of the solid wax and evaporation of the liquid forms the physical change.

Chemical part: burning of the wax vapour forms the chemical change.

Explanation:

8 0
3 years ago
What is the ph of 0.00035 M KOH
pashok25 [27]

Answer:

13.5

Explanation:

Potassium hydroxide fully ionizes when dissolved in water according to the following equation:

K

O

H

→

K

+

+

O

H

−

Now, let's find the relationship between

K

O

H

and

O

H

−

1

  :  

1

ratio

⇒

[

K

O

H

]

=

[

O

H

−

]

=

6.7

×

10

−

3

M

In any aqueous solution,

[

H

3

O

+

]

and

[

O

H

−

]

must satisfy the following condition:

[

H

3

O

+

]

[

O

H

−

]

=

K

w

[

H

3

O

+

]

=

K

w

[

O

H

−

]

[

H

3

O

+

]

=

1.0

×

10

−

14

6.7

×

10

−

3

[

H

3

O

+

]

=

1.5

×

10

−

12

M

Now, after finding the concentration of the hydronium ion, the pH of the solution is determined:

p

H

=

−

log

[

H

3

O

+

]

p

H

=

−

log

[

1.5

×

10

−

12

]

p

H

=

11.83

Other Method

Find the pOH using the concentration of the hydroxide ion, then use the formula

p

H

+

P

O

H

=

14

to find the pH.

8 0
3 years ago
T or F: The mass of an answer is so small it is rounded to 0 amu
Nutka1998 [239]
True because it doesn’t count as a full number
6 0
3 years ago
A sample of Xe takes 75 seconds to effuse out of a container. An unknown gas takes 60 seconds to effuse out of the identical con
miss Akunina [59]

Answer:

Kr

Explanation:

Now we have to apply Graham's law of diffusion in gases

t1/t2 = √M1/M2

If t1 is the time of diffusion of Xe = 75 seconds

t2 is the time of diffusion of the unknown gas = 60 seconds

M1= molar mass of Xe=131.293

M2= molar mass of the unknown gas

Thus;

75/60 = √131.293/M2

(75/60)^2= (√131.293/M2)^2

5625/3600=131.293/M2

M2= 3600×131.293/5625

M2= 84.0

The unknown gas is krypton (Kr)

8 0
3 years ago
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