Answer: acid dissociation constant Ka= 2.00×10^-7
Explanation:
For the reaction
HA + H20. ----> H3O+ A-
Initially: C. 0. 0
After : C-Cx. Cx. Cx
Ka= [H3O+][A-]/[HA]
Ka= Cx × Cx/C-Cx
Ka= C²X²/C(1-x)
Ka= Cx²/1-x
Where x is degree of dissociation = 0.1% = 0.001 and c is the concentration =0.2
Ka= 0.2(0.001²)/(1-0.001)
Ka= 2.00×10^-7
Therefore the dissociation constant is
2.00×10^-7
KE = (1/2)(m)(v^2)
KE = (1/2)(7)(4^2)
KE = (1/2)(112)
KE = 56 J
Answer:
a) 24.31 g
b) 16.69 g
Explanation:
A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.
After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.
Therefore, Pressure of Kr = 0.193 atm
Pressure of CO2 = 0.729 - 0.193 = 0.536 atm
Their mole fraction can be also determined as follows:
CO2 = 
CO2 = 
= 0.735
Also; for Kr ; we have
Kr =
Kr = 0.265
Molar mass of CO2 = 44 g/mol
Molar mass of Kr = 83.78 g/mol
Mass of CO2 = mole fraction * molar mass = 0.735 * 44 = 32.34
Mass of Kr = 0.265 * 83.78 = 22.20
Total mass = 32.34 +22.20 = 54.54
The Percentage of gas in mixture is as follows:
% CO2 =
* 100 %
= 0.5930
= 59.30%
(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g
% Kr =
* 100 %
= 0.407
= 40.70 %
(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g
Answer:
the quantity of solution to moles for d is significantly lower.
Explanation:
the larger the amount of liquid, the less amount of ions to dissociate hence having a lesser amount of chloride ions.
compared to b which is less liquid and a higher concentration