You are given
the density of helium and neon gas mixture which is 0.1562 grams per liters at 40.2degC and 296 torr. You are required to find the mole fraction of neon in this mmixture.
c = dRT/P
c = (0.1562g/L)(0.08206 L-atm/mol-K)(40.2+273)K/296torr(1atm/760torr)
c = 10.31 g/mol
since helium is 4 g/mol
mole fraction of neon = (10.31 - 4) / 10.31 = 0.612
Answer: Electrons have a negative charge
We use the Boyle's law to solve this question. At constant temperature, the volume of a fixed mass of a gas is inversely proportional to its pressure. When comparing the fixed mass of gas at different conditions under this law, the expression below is used.
P₁V₁=P₂V₂
P₁=5.0 atm
P₂=7.0atm
V₁=3.5 L
V₂=V
5.0×3.5=7.0×V
V= (5.0×3.5)7.0
V=2.5 L
Answer:
HEAT REQUIRED TO RAISE THE TEMPERATURE OF 179 ACETIC ACID FROM 25 °C TO 82.7°C IS 21 100j OR 21.1 kJ
Explanation:
Heat = mcΔT
m = 179 g
C = 2.043 J.g-1K-1
ΔT = ( 82.70 - 25 ) = 57.7°C
Heat = 179 * 2.043 * 57.7
Heat = 21, 100.72 J
Heat ≅ 21.1 kJ
Yes because the cold water has slower moving molecules.