<h3>
Answer:</h3>
23.459 g NaNO₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN] H₂SO₄ + 2NaNO₂ → 2HNO₂ + Na₂SO₄
[Given] 24.14714 g Na₂SO₄
<u>Step 2: Identify Conversions</u>
[RxN] 1 mol Na₂SO₄ = 2 mol NaNO₂
Molar Mass of Na - 22.99 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of Na₂SO₄ - 2(22.99) + 32.07 + 4(16.00) = 142.05 g/mol
Molar Mass of NaNO₂ - 22.99 + 14.01 + 2(16.00) = 69.00 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We need 5 sig figs (instructed).</em>
23.4587 g NaNO₂ ≈ 23.459 g NaNO₂
pH of solution = 13.033
<h3>Further explanation</h3>
Given
2.31 g Ba(OH)₂
250 ml water
Required
pH of solution
Solution
Barium hydroxide is fully ionized, means that Ba(OH)₂ is a strong base
So we use a strong base formula to find the pH
[OH ⁻] = b. Mb where
b = number of OH⁻
/base valence
Mb = strong base concentration
Molarity of Ba(OH)₂(MW=171.34 g/mol) :

Ba(OH)₂ ⇒ Ba²⁺ + 2OH⁻(b=valence=2)
[OH⁻]= 2 . 0.054
[OH⁻] = 0.108
pOH= - log 0.108
pOH=0.967
pOH+pH=14
pH=14-0.967
pH=13.033
Answer:
Balanced chemical equation:
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
Explanation:
Chemical equation:
Al + H₂SO₄ → Al₂(SO₄)₃ + H₂
Balanced chemical equation:
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
Steps:
Let balance the SO₄ first.
Al + 3H₂SO₄ → Al₂(SO₄)₃ + H₂
There are three H₂ on left so put the coefficient three on right too.
Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
Two Al on right and one on left so we will put the coefficient two on left.
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂
All atoms are correctly balanced.
Answer:
Cl2, Chlorine molecule has a boiling point closest to that of argon.
This is because Chlorine is made up of discrete and simple molecules making up a simple molecular structure. The molecules associate through weak van der waal's forces of attraction hence low boiling point.
HCl <em>has</em><em> </em><em>strong</em><em> </em><em>hydrogen</em><em> </em><em>bonds</em><em>.</em>
F2 <em>is</em><em> </em><em>very</em><em> </em><em>small</em><em> </em><em>hence</em><em> </em><em>strong</em><em> </em><em>forces</em><em> </em><em>of</em><em> </em><em>attraction</em><em>.</em>
HF <em>has</em><em> </em><em>strong</em><em> </em><em>hydr</em><em>ogen</em><em> bonds</em>