Answer:

Explanation:
Given:
- dimension of square plate,

- thickness of fluid layer,

- force on the fluid due to plate,

- velocity of plate,

<u>Using Newton's law of viscosity:</u>
..........................................(1)
where:
shear force on the surface on the fluid
coefficient of (dynamic) viscosity
Now, shear force:


Putting respective values in eq.(1)


Answer:
181.54 K
Explanation:
From gas laws, we know that v1/t1= v2/t2 where v and t represent volume and temperatures, 1 and 2 for the first and second container. Making t2 the subject of the formula then
T2=v2t1/ v1
Given information
V1 435 ml
V2 265 ml
T1 298K
Substituting the given values then
T2=265*298/435=181.54 K
I think there is only one.
<span>
</span>Both are conserved<span>.</span>