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Olin [163]
3 years ago
15

A ball is whirled on the end of a string in a horizontal circle of radius R at a speed v. Complete the following statement: The

centripetal acceleration of the ball can be increased by a factor of 8 by ________.
Physics
2 answers:
JulijaS [17]3 years ago
7 0

Explanation:

When an object moves in a circular path, centripetal force acts on it. The magnitude of centripetal acceleration is given by formula :

a=\dfrac{v^2}{r}

Here,

v is the speed of the ball in circular path

r is the radius of circular path

The centripetal acceleration is inversely proportional to the radius of the circular path. To increase the centripetal acceleration by a factor of 8, the radius must decrease by a factor of 8 keeping speed constant.

ICE Princess25 [194]3 years ago
7 0

Answer:

Explanation:

The formula of the centripetal acceleration is given by

a=\frac{v^{2}}{R}

The centripetal acceleration is increased by 8 times, it means the velocity is doubled and the radius is halved.

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0 = <em>t</em> (14 m/s - 1/2 <em>g</em> <em>t</em>)

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<em>y</em> = (14 m/s) (5 s - 2.86 s) - 1/2 <em>g</em> (5 s - 2.86 s)²

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(ii) The ball will technically keep bouncing forever, since the speed of the ball is only getting halved each time it bounces. But <em>y</em> will converge to 0 as <em>t</em> gets arbitrarily larger. We can't realistically answer this question without being given some threshold for deciding when the ball is perfectly still.

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0 = <em>t</em> (3.5 m/s - 1/2 <em>g</em> <em>t</em>)

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(iv) <em>v</em> = 7 m/s - <em>g</em> (6 s - 5.72 s) ≈ 4.26 m/s

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