Explanation:
When an object moves in a circular path, centripetal force acts on it. The magnitude of centripetal acceleration is given by formula :
Here,
v is the speed of the ball in circular path
r is the radius of circular path
The centripetal acceleration is inversely proportional to the radius of the circular path. To increase the centripetal acceleration by a factor of 8, the radius must decrease by a factor of 8 keeping speed constant.
Answer:
At low pressure-
At high pressure-
Explanation:
Initial speed,
Final speed,
Net horizontal force due to rolling friction mg where m is mass, g is acceleration due to gravity,
is coefficient of rolling friction
From kinematic relation,
For each tire,
Making the subject
Under low pressure of 40 Psi, d=18 m
Therefore,
At a pressure of 105 Psi, d=93.7
Therefore,
Answer:
21870.3156 N
Explanation:
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 1.6 m/s²
Equation of motion
The acceleration of the craft should be 1.02234 m/s²
Weight of the craft
Thrust
The thrust needed to reduce the velocity to zero at the instant when the craft touches the lunar surface is 21870.3156 N