A ball is whirled on the end of a string in a horizontal circle of radius R at a speed v. Complete the following statement: The
2 answers:
Explanation:
When an object moves in a circular path, centripetal force acts on it. The magnitude of centripetal acceleration is given by formula :
Here,
v is the speed of the ball in circular path
r is the radius of circular path
The centripetal acceleration is inversely proportional to the radius of the circular path. To increase the centripetal acceleration by a factor of 8, the radius must decrease by a factor of 8 keeping speed constant.
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Answer:
The magnitude of the force F is given by
F = ( +
+
) *(
*g/(
))
Explanation:
Given there are three blocks of masses ,
and
(ref image in attachment)
When all three masses move together at an acceleration a, the force F is given by
F = ( +
+
) *a ................(equation 1)
Also it is given that does not move with respect to
, which gives tension T is exerted on pulley by
only, Hence tension T is
T = *a ..........(equation 2)
There is also also tension exerted by . There are two components here: horizontal due to acceleration a and vertical component due to gravity g. Thus tension is given by
T =
................(equation 3)
From equation 2 and 3, we get
*a =
Squaring both sides we get
*
=
* (
+
)
*
= (
*
)+ (
*
)
( -
) *
=
*
=
*
/(
-
)
Taking square root on both sides, we get acceleration a
a = *g/(
)
Hence substituting the value of a in equation 1, we get
F = ( +
+
) *(
*g/(
))
