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Olin [163]
4 years ago
15

A ball is whirled on the end of a string in a horizontal circle of radius R at a speed v. Complete the following statement: The

centripetal acceleration of the ball can be increased by a factor of 8 by ________.
Physics
2 answers:
JulijaS [17]4 years ago
7 0

Explanation:

When an object moves in a circular path, centripetal force acts on it. The magnitude of centripetal acceleration is given by formula :

a=\dfrac{v^2}{r}

Here,

v is the speed of the ball in circular path

r is the radius of circular path

The centripetal acceleration is inversely proportional to the radius of the circular path. To increase the centripetal acceleration by a factor of 8, the radius must decrease by a factor of 8 keeping speed constant.

ICE Princess25 [194]4 years ago
7 0

Answer:

Explanation:

The formula of the centripetal acceleration is given by

a=\frac{v^{2}}{R}

The centripetal acceleration is increased by 8 times, it means the velocity is doubled and the radius is halved.

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Generally,

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Then, when x(t) = 9.6cm

9.6 = 11.6 Cos(3.92t)

Cos(3.922t) = 9.6/11.6

Cos(3.922t) = 0.8276

3.922t = ArcCos(0.8276)

Note: the angle is in radiant

3.922t = 0.596

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t = 0.152 second

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v(t) = x'(t) = -11.6×3.92Sin(3.922t)

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Now, when t =0.152

v(t) = -45.5 Sin(3.922×0.152)

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Magnitude of the acceleration is 147.68 cm/s²

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