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3 years ago

A ball of mass 45kg thrown upward with a velocity of 40m/s

Physics

1 answer:

AnnyKZ [126]3 years ago

4 0

1) KE=1/2*m*v^2
1/2*45*40^2
KE=36,000J

2) PE=mgh
45*9.81*30
PE=13243.5J

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Answer:

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Explanation:

The spring system in the taptap obey's Hooke's law, which states that:

$F=kx$

where

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k is the spring constant

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In this problem:

- The force applied is the weight of the driver of mass m = 69 kg, so

$F=mg=(69 kg)(9.8 m/s^2)=676.2 N$

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$x=2\cdot 10^{-2} m=0.02 m$

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3 years ago

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sergij07 [2.7K]

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2 years ago

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A scientific model is a way of representing a system to better understand it's behavior

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2 years ago

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Re-arranging the formula, we have
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And since the force is attractive, the two charges must have opposite sign, so the charge q must have negative sign.

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3 years ago

An initially motionless test car is accelerated uniformly to 120 km/h in 8.28 s before striking a simulated deer. The car is in

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Answer:

The value is $a = 4.0 \ m/s^2$