Flux through each of the six faces of the cube: 
Explanation:
In this problem, a charge
is placed at the center of the cube.
We can apply Gauss Law, which states that the flux through the surface of the cube is equal to the charge contained within the cube divided by the vacuum permittivity; mathematically:

where
is the charge
is the vacuum permittivity
Here we want to find the flux through each of the six faces of the cube.
By simmetry, we can say that the 6 faces are identical: therefore, the flux through each of them must be the same. This means that the flux through each faces is 1/6 of the total flux through the total surface, therefore:

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Answer:
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Explanation: