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lukranit [14]
3 years ago
10

1. Hydrogen, Helium, Lithium?

Chemistry
1 answer:
Reika [66]3 years ago
6 0

Answer:

what happened to it, have the gone extinct

You might be interested in
draw the structure of a compound with the formula c9h20 that has two non-adjacent chirality centers, both r.
4vir4ik [10]

Answer:

.

Explanation:

6 0
3 years ago
Draw stearic acid (octadecanoic acid). You do not need to draw hydrogen atoms attached to carbon atoms.
postnew [5]

Answer:

The structure of stearic acid (octadecanoic acid) is shown in the attachment below

Explanation:

Stearic acid is an example of a saturated fatty acid. The structure of stearic acid is shown in the attachment below.

5 0
3 years ago
A 5.41 g sample of carbon reacts with hydrogen to form 6.32 g of an organic compound. What is the empirical formula of the organ
zhannawk [14.2K]

Answer:

CH₂

Explanation:

From the question given above, the following data were obtained:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Empirical formula =?

Next, we shall determine the mass of Hydrogen (H) in the compound. This can be obtained as follow:

Mass of Carbon (C) = 5.41 g

Mass of compound = 6.32 g

Mass of Hydrogen (H) =?

Mass of H = mass of compound – mass of C

Mass of H = 6.32 – 5.41

Mass of H = 0.91 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of C = 5.41 g

Mass of H = 0.91 g

Divide by their molar mass

C = 5.41 / 12 = 0.451

H = 0.91 / 1 = 0.91

Divide by the smallest

C = 0.451 / 0.451 = 1

H = 0.91 / 0.451 = 2

Thus, the empirical formula for the compound is CH₂

3 0
3 years ago
What elements are most commonly used in wiring?
Schach [20]

Answer:

Hi myself Shrushtee.

Explanation:

Wire Materials: The most common material for electrical wire is copper and aluminum, these are not the best conductors however they are abundant and low cost. Gold is also used in applications because it is corrosion resistant.

please mark me as brainleist

6 0
3 years ago
To interconvert the concentration units molality (m) and mass percent, you must also know the density of the solution. A) True B
uranmaximum [27]

Answer:

The correct answer is option false.

Explanation:

Molality of the solution defined as moles of substance present in 1 kilogram of   solvent.

Moles = \frac{Mass of solute}}{\text{molar mass of solute}}

Molality=\frac{Moles}{\text{Mass of solvent(kg)}}

Mass of percent (w/w%) of the solution is defined as amount of solute present in 100 grams of solution.

(w/w\%)_=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

So, if want to inter-convert molality into mass percent we can do that without knowing density of solution.

Mass of solution = Mass of solute + Mass of solvent

7 0
4 years ago
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