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lukranit [14]
3 years ago
10

1. Hydrogen, Helium, Lithium?

Chemistry
1 answer:
Reika [66]3 years ago
6 0

Answer:

what happened to it, have the gone extinct

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A student mixes sugar and water until the sugar dissolves. This an example of a<br> HELP PLS !!
murzikaleks [220]

Answer:

The sugar water mix is a mixture.

6 0
3 years ago
Determine the empirical formula of a
k0ka [10]

Answer:

AuCl

Explanation:

Given parameters:

Mass of Gold  = 2.6444g

Mass of Chlorine  = 0.476g

Unknown:

Empirical formula  = ?

Solution:

Empirical formula is the simplest formula of a compound. Here is the way of determining this formula.

Elements                                     Au                                             Cl

Mass                                         2.6444                                     0.476

Molar mass                                 197                                          35.5

Number of moles                  2.6444/197                                 0.476/35.5

                                                 0.013                                           0.013

Divide by the

smallest                                 0.013/0.013                                 0.013/0.013

                                                       1                                                   1

The empirical formula of the compound is AuCl

3 0
2 years ago
if you dilute 25.4mL of a 3.5M solution to make 166.7mL of solution, what is the molarity of the dilute solution
Anna11 [10]
Molarity=(initial molarityxinitial volume)/final volume
M=(3.5x25.4)/166.7=0.533 M
8 0
3 years ago
If 28 grams of N reacts completely with 12 grams of H2, then how many
Bogdan [553]

Answer:

Mass of NH₃ produced = 34 g

Explanation:

Given data:

Mass of nitrogen = 28 g

Mass of Hydrogen = 12 g

Mass of NH₃ produced = ?

Solution:

Chemical equation:

N₂ +  3H₂    →   2NH₃

Moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 28 g/ 28 g/mol

Number of moles = 1 mol

Moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 12 g/ 2 g/mol

Number of moles = 6 mol

Now we will compare the moles of hydrogen and nitrogen with ammonia.

                            H₂              :               NH₃

                            3                :                2

                            6                :             2/3×6 = 4 mol

                           N₂              :                NH₃

                            1                :                 2

Number of moles of ammonia produced by nitrogen are less thus it will act as limiting reactant.

Mass of ammonia produced:

Mass = number of moles × molar mass

Mass =  2 mol  ×  17 g/mol

Mass = 34 g

                     

5 0
3 years ago
Read 2 more answers
Please help! trying to past :((
Margaret [11]

the block will move to F but at the same time make it's way over to G because 250g weighs more than 100g

3 0
3 years ago
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