The Ksp of Mg(OH)2 in water is 1.8 x 10-<span>11. This means that in pure water, Mg(OH)2 has a solubility of:
</span>∛[(1.8 x 10-11) / 4] = 1.65 x 10-4 mol/L
<span>which is equal to
</span>1.65 x 10-4<span> mol x (58.32) / 10 x 100 mL = 9.62 x 10-4g / 1x102 mL
If the pH is 12, the hydroxide concentration in the solvent is
10^-(14-12) = 0.01 mol/L
The solubility is solve using the formula
</span>1.8 x 10-11 = x (2(0.01 + x))^2
x = 4.5x10-8 mol/L
which is equal to
4.5x10-8 mol x (58.32) / 10 x 100 mL = 2.62 x 10-7g / 1x102 mL
Answer:
Balance chemical equation is
O2(g) + 2H2(g) --> 2H20(g)
a. 0.20 mol 02 --> 0.225mol H20
b. 0.30 mol H2 --> 2.7mol H20
The maximum amount of hydrogen gas that can be prepared is if all the hydrogen from both compounds is released.
The hydrogen in 4.94 g of SrH2 is calculated from the mass ratios between Sr and H
1) H2 in SrH2
Sr atomic mass = 87.62 g/mol
H2 molar mass = 2.02 g/mol
Mass of 1 mol of SrH2 = 87.62 g / mol + 2.02 g/mol = 89.64 g/mol
Ratio of H2 to SrH2 = 2.02 g H2 / 89.64 g SrH2
Proportion: 2.02 g H2 / 89.64 gSrH2 = x / 4.93 g SrH2
=> x = 4.93 g SrH2 * 2.02 g H2 / 89.64 g SrH2 = 0.111 g H2
2) H2 in H2O
2.02 g H2 / 18.02 g H2O * 4.14 g H2O = 0.464 g H2
3) Total mass of hydrogen = 0.111 g + 0.464 g = 0.575 g
Answer: 0.575 g
We are given with a vinegar with a hydrogen ion concentration of 0.00010 m. We are asked to express this concentration in scientific notation. The answer when expressed in scientific notation is 1x10^-4 m or molality. Answer is <span>1x10^-4 m. </span>
