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ki77a [65]
3 years ago
14

If a car travels at 35 m/s, how much time does it take to travel 200 m?

Physics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer:  7 hours....

Explanation:

TiliK225 [7]3 years ago
3 0

Answer:

{ \rm{time =  \frac{distance}{speed} }} \\  \\ { \rm{time =  \frac{200}{35} }} \\  \\ { \boxed{ \rm{ \: time = 5.71 \: seconds}}}

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A 0.119 kg ball is dropped from rest. if the magnitude of the ball's momentum is 0.817 kg·m/s just before it lands on the ground
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8 0
3 years ago
State the Boyle's Law. If the graph for Boyle's law is straight line through the origin then state the quantity taken along: a)
astraxan [27]

Answer:

(a) X- axis represent (1/P) inverse of pressure

(b) Y-axis represent (V) volume

Explanation:

Boyle's Law States that at constant temperature, the volume of a fixed mass of gas is inversly proportional to its pressure. It can be expressed mathematically as

V α 1/P

VPα1

removing the proportionality sign and introducing a constant

VP = k

V₁P₁ = V₂P₂

Where V₁ and V₂ are initial and final volume respectively, P₁ and P₂ are initial and final pressure respectively.

If the graph for Boyle's law is straight line through the origin,

(a) X-axis represent (1/P) inverse of pressure

(b) Y- axis represent (V) volume.

7 0
3 years ago
. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
3 years ago
Calculate the hydrostatic difference in blood pressure between the brain and the foot in a person of height 1.93 m. The density
Slav-nsk [51]

Answer:

Explanation:

Given: Density of blood = 1.03 × 10³ Kg/m³, Height =  1.93 m g = 9.8 m/s²

pressure at the brain is equal to atmospheric pressure. = Hydro-static

pressure(ρ₀)

∴ pressure of the foot = pressure of the brain(ρ₀) + ( density of blood × acceleration due to gravity × height)(ρgh)

Hydro-static pressure = pressure at the feet- pressure at the brain(ρ₀)

Hydro-static pressure (Δp) = (ρgh + ρ₀) - ρ₀ = ρgh

Hydro-static pressure = 1.03 × 10³ × 9.8 × 1.93 = 1.948 × 10⁴ Pa

∴  Hydro-static pressure ≈ 1.95 × 10⁴ Pa

3 0
3 years ago
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