Answer:
63 degrees
Step-by-step explanation:
(180-54)/2=126/2=63
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
(f+g)(3) = f(3) + g(3) = 6(3) + 3 + 3 -7 = 18 +6 -7 = 17.
Answer: 17
To find the rate, we have to divide both numbers by 5. So the rate will be $1.592 for 1 pound.
