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3 years ago

Describe some characteristics of a prokaryotic cell

Chemistry

2 answers:

ss7ja [257]3 years ago

8 0

Answer:12121

Explanation:

alina1380 [7]3 years ago

6 0

Answer:

- they don't have a nucleus and other membrane-bound organelles

- its DNA is found in the nucleoid

- the cell wall is extra protection, helps keep the cell's shape, and prevents dehydration

- their small size allows the quick entry and diffusion of ions and molecules to other parts of the cell while also allowing fast removal of waste products out of the cell

Explanation:

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When a solution of NaI reacts with a solution of AgNO3, what is the net ionic equation?

Leni [432]

Answer:

Ag⁺(aq) + I⁻(aq) → AgI(s)

Explanation:

Net ionic equation is a way to write a chemical equation in which you are listing only the species that are participating in the reaction.

In the reaction:

AgNO₃(aq) + NaI(aq) → AgI(s) + NaNO₃(aq).

The ionic equation is:

Ag⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + I⁻(aq) → AgI(s) + Na⁺(aq) + NO₃⁻(aq).

Now, listing only the species that are participating in the reaction:

3 0

3 years ago

Two containers, one with a volume of 3.0 L and the other with a volume of 2.0 L contain, respectively, argon gas at 1.1 atm and

aalyn [17]

Answer:

a. $p_T=0.93atm$ .

$p_{Ar}=0.66atm\\\\p_{He}=0.3atm$

$x_{Ar}=0.6875\\\\x_{He}=0.3125$

Explanation:

Hello,

In this case, considering that the valve is opened, we can use the Boyle's law in order to compute the final pressure of argon by considering its initial pressure and volume and a final volume of 5.0 L:

$p_{Ar}=\frac{1.1atm*3.0L}{5.0L}=0.66atm$

And the final pressure of helium:

$p_{He}=\frac{0.75atm*2.0L}{5.0L}=0.3atm$

Which actually are the partial pressure of both of them, it means that the total pressure is:

Finally, the mole fraction of each gas is computed by considering the Dalton's law:

$x_i=\frac{p_i}{p_T}$

$x_{Ar}=\frac{0.66atm}{0.93atm} =0.6875\\\\x_{He}=\frac{0.3atm}{0.93atm} =0.3125$

Best regards.

6 0

3 years ago

If 5 mol of oxygen gas effuses through an opening in 10 seconds, how long will it take for the same amount of hydrogen gas to ef

andrezito [222]

Answer:

Explanation:

Recall the law of effusion:

$\displaystyle \frac{r_1}{r_2} = \sqrt{ \frac{\mathcal{M}_2}{\mathcal{M}_1} }$

Because 5 mol of oxygen was effused in 10 seconds, the rate is 0.5 mol/s.

Let the rate of oxygen be <em>r</em>₁ and the rate of hydrogen be <em>r</em>₂.

The molecular weight of oxygen gas is 32.00 g/mol and the molecular weight of hydrogen gas is 2.02 g/mol.

Substitute and solve for <em>r</em>₂:

$\displaystyle \begin{aligned} \frac{(0.5\text{ mol/s})}{r_2} & = \sqrt{\frac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}} \\ \\ r_2 & = \frac{0.5\text{ mol/s}}{\sqrt{\dfrac{(2.02\text{ g/mol})}{(32.00\text{ g/mol})}}} \\ \\ & = 2.0\text{ mol/s}\end{aligned}$

Because there are 5 moles of hydrogen gas:

$\displaystyle 5.0\text{ mol} \cdot \frac{1\text{ s}}{2.0\text{ mol}} = 2.5\text{ s}$

In conclusion, it will take about 2.5 seconds for the hydrogen gas to effuse.

Check: Because hydrogen gas is lighter than oxygen gas, we expect that hydrogen gas will effuse quicker than oxygen gas.

6 0

3 years ago

during which step of the scientific method does a scientist make an educated guess about the outcome of an experiment

wariber [46]

hypothesis statement or the very beginning.

7 0

4 years ago

Read 2 more answers

Write a conclusion statement that addresses the following questions: • Explain what the color change indicated about the changes

Novay_Z [31]

Answer: try to understand coz the question is not valid

Explanation: Explain the relationship between forward and reverse reactions at equilibrium and predict how changing the amount of a reactant or product (creating a stress) will affect that relationship.For example (select one from each underlined section)If the amount of (reactant or product) increases, the rate of the (forward or reverse)reaction will (increase or decrease)to reach a new equilibrium. If the amount of (reactant or product) decreases, the rate of the (forward or reverse)reaction will (increase or decrease)to reach a new equilibrium. Procedure: Access the virtual lab and complete the inquiry experiment

5 0

3 years ago