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xxMikexx [17]
3 years ago
6

Question 1 of 10

Chemistry
1 answer:
Alina [70]3 years ago
6 0

D. The total number of gas molecules will decrease.

Explanation:

According to Le Chatelier's principle, an increase in pressure in a system involving gases will cause the total number of gas molecules to decrease.

Le Chatelier's principle states that "if any conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".

In a reaction involving gases, a change in pressure affects only reactions in a gaseous phase.

An increase in pressure on an equilibrium system will shift the position of the equilibrium to the side having smaller volume and vice versa.

learn more:

Equilibrium brainly.com/question/10838453

#learnwithBrainly

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Which part of the atom is involved in chemical bonding with other atoms?
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A sample of gas occupies a volume of 61.5 mL . As it expands, it does 130.1 J of work on its surroundings at a constant pressure
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Answer:

the final volume of the gas is V_2 = 1311.5 mL

Explanation:

Given that:

a sample gas has an initial volume of 61.5 mL

The workdone = 130.1 J

Pressure = 783 torr

The objective is to determine the final volume of the gas.

Since the process does 130.1 J of work on its surroundings at a constant pressure of 783 Torr. Then, the pressure is external.

Converting the external pressure to atm ; we have

External Pressure P_{ext}:

P_{ext} = 783 \ torr \times \dfrac{1 \ atm}{760 \ torr}

P_{ext} = 1.03 \ atm

The workdone W = P_{ext}V

The change in volume ΔV= \dfrac{W}{P_{ext}}

ΔV = \dfrac{130.1 \ J  \times \dfrac{1 \ L  \ atm}{ 101.325 \ J}  }{1.03 \ atm }

ΔV = \dfrac{1.28398717 }{1.03  }

ΔV = 1.25 L

ΔV = 1250 mL

Recall that the initial  volume = 61.5 mL

The change in volume V is \Delta V = V_2 -V_1

-  V_2= -  \Delta V  -V_1

multiply through by (-), we have:

V_2=   \Delta V+V_1

V_2 =  1250 mL + 61.5 mL

V_2 = 1311.5 mL

∴ the final volume of the gas is V_2 = 1311.5 mL

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