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melisa1 [442]
3 years ago
6

If solid become liquid can it become solid again

Chemistry
1 answer:
velikii [3]3 years ago
3 0

Answer:

Yes!  It's because of like freezing and or solidification. It's the phase transition in which a liquid turns into a solid. It's when the temperature is lowered to or below a type of  freezing point.

Explanation:

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Which of the following changes alone would cause a decrease in the value of Keq for the reaction represented above?A) Decreasing
Orlov [11]

Answer:

Explanation:

You did not provide the reaction. However, you should know that only change in temperature affects the value of an equilibrium constant (Keq) by the equation, K=Ae>-RT

5 0
3 years ago
Zuzana tests a common household substance and finds that it has a pH of 3.
horrorfan [7]
A pH of 3 is acidic! hope this helps:)

a pH of 0-6 is acidic
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a pH of 8-14 is basic
4 0
3 years ago
A sealed vessel contains 0.200 mol of oxygen gas, 0.100 mol of nitrogen gas, and 0.200 mol of argon gas. The total pressure of t
babunello [35]

Answer:

D

Explanation:

We can use the mole ratio to calculate the partial pressure. The total number of moles is 0.2 + 0.2 + 0.1 = 0.5 moles

Now, we know that the mole fraction of the argon gas would be 0.2/0.5

The partial pressure is as follows. To calculate this, we simple multiply the number of moles by the total pressure.

0.2/0.5 * 5 = 1.0/0.5 = 2.00atm

D

8 0
3 years ago
Proper significant figure: 27.01 + 14.369
Paul [167]

Answer:

<h2>put the bigger number on top then add </h2>

Explanation:

41.369

8 0
3 years ago
A gas sample with a mass of 12.8 g exerts a pressure of 1.2 atm at 15°c and a volume of 3.94 l. what is the molar mass of the ga
Kryger [21]
We can use the ideal gas law equation to find the number of moles in the gas
PV = nRTwhere P - pressure - 1.2 atm x 101 325 Pa/atm = 121 590 Pa
V - volume - 3.94 x 10⁻³ m³
n - number of moles 
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 15 °C + 273 = 288 K
substituting the values in the equation 
121 590 Pa x 3.94 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 288 K
n = 0.200 mol
molar mass of gas is = mass / number of moles 
molar mass = 12.8 g / 0.200 mol = 64 g/mol 
molar mass of gas is 64 g/mol
3 0
3 years ago
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