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3 years ago

If solid become liquid can it become solid again

Chemistry

1 answer:

velikii [3]3 years ago

3 0

Answer:

Yes! It's because of like freezing and or solidification. It's the phase transition in which a liquid turns into a solid. It's when the temperature is lowered to or below a type of freezing point.

Explanation:

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Setler [38]

The answer would be 3 cm. you round down to the nearest whole number when it is less than 5. you round up when it is 5 or more.

3 0

3 years ago

Read 2 more answers

A sample of hydrogen gas is placed in a 0.500 L container at 295K. The gas pressure is 1.442 bar. How many moles of H2 gas are i

steposvetlana [31]

Answer:

0.0294

Explanation:

5 0

3 years ago

Be sure to answer all parts. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. H2(g) + CO2(g) ⇌ H2O(g) +

nikklg [1K]

<u>Answer:</u>

<u>For 1:</u> The value of $\Delta G$ for the chemical equation is -24.636 kJ/mol

<u>For 2:</u> The value of $\Delta G$ for the chemical equation is -20.925 kJ/mol

<u>Explanation:</u>

For the given chemical equation:

$H_2(g)+CO_2(g)\rightleftharpoons H_2O(g)+CO(g)$

<u>For 1:</u>

To calculate the $\Delta G$ for given value of equilibrium constant, we use the relation:

$\Delta G=-RT\ln K_p$ .....(1)

where,

$\Delta G$ = ? kJ/mol

R = Gas constant = $8.314J/K mol$

T = temperature = 2000 K

$K_p$ = equilibrium constant in terms of partial pressure = 4.40

Putting values in above equation, we get:

$\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (4.40)\\\\\Delta G=-24636.12J/mol$

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -24636.12 J/mol = -24.636 kJ/mol

Hence, the value of $\Delta G$ for the chemical equation is -24.636 kJ/mol

<u>For 2:</u>

The expression of $K_p$ for the given chemical equation is:

$K_p=\frac{p_{CO}p_{H_2O}}{p_{H_2}p_{CO_2}}$

We are given:

$p_{CO}=1.18atm\\p_{H_2O}=0.66atm\\p_{CO_2}=0.82atm\\p_{H_2}=0.27atm$

Putting values in above equation, we get:

$K_p=\frac{1.18\times 0.66}{0.27\times 0.82}\\\\K_p=3.52$

Now, calculating the value of $\Delta G$ by using equation 1:

R = Gas constant = $8.314J/K mol$

T = temperature = 2000 K

$K_p$ = equilibrium constant in terms of partial pressure = 3.52

Putting values in equation 1, we get:

$\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (3.52)\\\\\Delta G=-20925.68J/mol$

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -20925.68 J/mol = -20.925 kJ/mol

Hence, the value of $\Delta G$ for the chemical equation is -20.925 kJ/mol

3 0

3 years ago

Read 2 more answers

Need help !!!!! ASAP

Julli [10]

<h2>Hello!</h2>

The answer is:

The new volume will be 1 L.

$V_{2}=1L$

To solve the problem, since we are given the volume and the first and the second pressure, to calculate the new volume, we need to assume that the temperature is constant.

To solve this problem, we need to use Boyle's Law. Boyle's Law establishes when the temperature is kept constant, the pressure and the volume will be proportional.

Boyle's Law equation is:

$P_{1}V_{1}=P_{2}V_{2}$