The amount of energy absorbed by the 325g of water is 57,057J. Details about calorimetry can be found below.
<h3>How to calculate energy?</h3>
The energy absorbed by a mass of substance can be calculated using the following formula;
Q = mc∆T
Where;
- Q = quantity of heat absorbed
- m = mass of substance
- c = specific heat capacity
- ∆T = change in temperature
Q = 325g × 4.18 × (92 - 50)
Q = 57,057J
Therefore, the amount of energy absorbed by the 325g of water is 57,057J.
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Answer:
2 M
Explanation:
The equation for molarity is "M = moles/liters"
Potassium chloride's atomic mass is 74.55, meaning one mole of KCl is equal to 74.55g. In the equation, 298g of KCl is being used. To find out how many moles this is, multiply 298g of KCl by (1 mol/74.55g of KCl) to get 4.0 moles. Now you can use the equation for molarity.
M = 4.0 moles/2 Liters
Answers are:
1) The balanced oxidation half reaction: 2I⁻(aq) → I₂(s) + 2e⁻.
Iodine is oxidized (lost electrons) from -1 to neutral charge (0).
2) The balanced reduction half-reaction: 2H₂O(l) + 2e⁻ → H₂(g) + 2OH⁻.
Hydrogen is reduced (gain electrons) from +1 to neutral charge.
3) The oxidation <span>reaction takes place at the anode.</span>
Answer:
Explanation:
*Since the titration is between the strong acid HCl and the strong base Ca(OH)2, the pH at the equivalent point should be 7. On interpolation, we will obtain that 9.50mL and 9.82 mL of HCl is required to completely neutralized the given Ca(OH)2 solution.
*pH at the equivalence point =7
we know that pH + pOH = 14
Hence pOH= 14-7=7
pOH= -log(OH-)
The concentration of OH-= 10-pH= 1X10-7 M
One reason for the low solubility may be the higher reaction temperature, Another reason is the common ion effect.
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