I believe that would be a parasitism because one organism benefits yet the other is harmed.
Answer:
116 years
Explanation:
To solve this, we will use the half life equation;
A(t) = A_o(½)^(t/t_½)
Where;
A(t) is the amount of strontium left after t years;
A_o is the initial quantity of strontium that will undergo decay;
t_½ is the half-life of strontium
t is the time it will take to decay
We are given;
A(t) = 7.5 g
A_o = 120 g
From online values, half life of strontium-90 is 29 years. Thus, t_½ = 29
Thus;
7.5 = 120 × ½^(t/29)
Divide both sides by 120 to get;
7.5/120 = ½^(t/29)
0.0625 = ½^(t/29)
In 0.0625 = (t/29) In ½
-2.772589 = (t/29) × (-0.693147)
(t/29) = -2.772589/(-0.693147)
t/29 = 4
t = 29 × 4
t = 116 years
Answer:
When the moles of the reactant is equal to the mole of the product.
Answer:
ozone (O3): inorganic
methane (CH4): organic
aluminum hydroxide (Al(OH)3): inorganic
butane (C4H10): organic
carbon monoxide (CO): inorganic
Explanation:
An inorganic compound is typically a chemical compound that lacks carbon–hydrogen bonds, that is, a compound that is not an organic compound. Some simple compounds that contain carbon are often considered inorganic. Examples of inorganic compounds include carbon monoxide , carbon dioxide , carbonates, carbides , cyanides, cyanates, and thiocyanates. Most of these compounds are normal parts of mostly organic systems, including living organisms. When a chemical substance is classified as inorganic, it does not necessarily mean that it does not occur within
living things.
Organic compounds typically contain the carbon-hydrogen bonds. The carbon atoms often catenate and most organic substances occur in living systems and are products of biochemical reactions in living organisms. However, organic substances can also be synthetic and can be prepared in the laboratory.
