The concentration of sulphur dioxide = 0.75 mol/litre, The concentration of Oxygen is 1.125 mol/litre, The concentration of sulphur trioxide is 1.75 mol/l.
<h3>What is a Balanced Equation ?</h3>
A equation in which the atoms of each element in the reactants and the products are same is called Balanced Equation .
The equation given is
2 SO₂(g) + O₂(g) 2 SO₃(g)
The initial moles of sulphur dioxide gas = 2.5 mol.
Initial Moles of Oxygen is 2 moles
The moles of sulphur dioxide gas at equilibrium is 0.75 mol
The mole ratio of sulphur dioxide to oxygen is 2:1
The mole ratio of sulphur dioxide to sulphur trioxide is 1 :1
The used up moles of sulphur dioxide is
2.5 - 0.75 = 1.75 mol
The oxygen required by 1.75 mole is 0.875 mol
The oxygen at equilibrium will be
2 -0.875
1.125 mol
The sulphur trioxide formed from 1.75 mol of sulphur dioxide at the equilibrium will be 1.75 mol.
Concentration = moles / Volume
Volume = 1L
Therefore the concentration of sulphur dioxide = 0.75 mol/litre
The concentration of Oxygen is 1.125 mol/litre
The concentration of sulphur trioxide is 1.75 mol/l.
To know more about a Balanced Equation
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