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AnnyKZ [126]
2 years ago
7

A circle passes through the vertices of a square of side 20cm.Find the radius of the circle.

Mathematics
2 answers:
erma4kov [3.2K]2 years ago
8 0

Answer:

14.1cm

Step-by-step explanation:

If a circle passes through the vertices of a square then the diagonal of a square is a circle diameter.

We use Pytagoras Theorem to find out the length (L)  of the diagonal given that:

L²  =  (20)²  +  (20)²

L²  = 2* (20)²

L  = √2 * 20

L  = 1,4142* 20

L = 28,28 cm

L diagonal in the square is a diameter of the circle then radius of a circle is:

r = L/2   ⇒   r  = 28,28 /2   ⇒   r = 14,14 cm

algol132 years ago
3 0

Answer:

14,1 cm

Step-by-step explanation:

If a circle passes through the vertices of a square then the diagonal of a square is a circle diameter.

We use Pytagoras Theorem to find out the length (L)  of the diagonal given that:

L²  =  (20)²  +  (20)²

L²  = 2* (20)²

L  = √2 * 20

L  = 1,4142* 20

L = 28,28 cm

L diagonal in the square is a diameter of the circle then radius of a circle is:

r = L/2   ⇒   r  = 28,28 /2   ⇒   r = 14,14 cm

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In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A
vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

\mu_s=np=500*0.90=450

The standard deviation will be:

\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

\mu=np=300*0.932=279.6

The standard deviation will be:

\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

P(270\leq x\leq280)=P(269.5

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

P(X=280)=P(279.5

8 0
3 years ago
Estimate the line of best fit using two points on the line.
denis23 [38]
Bom dia o sou já nasceu lá na fazendinha (8,5) é esse
3 0
3 years ago
Please please help please please help me please please help please please
USPshnik [31]

Answer:

Q2) A 0.5//// B 0.11//// C 1.7//// D 1.15//// E 2.13//// F 4.1

5 0
3 years ago
Help me ples!!!!!!!!!!!!!!!!!
bearhunter [10]
It would be subtraction I think
6 0
3 years ago
A. $20,950.75<br><br> B.$28,458.50<br><br> C.$31,045.50<br><br> D.$34,650.75
quester [9]

Answer:

C) 31,045.50

Step-by-step explanation:

<em>p*</em>855= amount of money made from sold products

You must subtract the amount of money spent from the amount of money made from sold products.

213750-6780=206970

To find the amount that the CEO of the company owned, you must multiply the number by 15% or 0.15:

206970*0.15= $31045.50

Therefor, the CEO made $31,045.50 that month.

4 0
2 years ago
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