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lisov135 [29]
3 years ago
10

What is a line spectrum?

Chemistry
1 answer:
Yanka [14]3 years ago
3 0

Answer: B

Explanation:

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What is the main idea of thomas paines the crisis ​
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The main idea was that the best thing for the American people to do was to fight for their independence from Great Britain.

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The household substances that will turn blue litmus paper red are: A) bleach and D) Vinegar. This is because bleach contains acidic solutions; and vinegar contains a percentage of organic acids for example, acetic acid.  

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Gold has an atomic weight of 196.97 g/mol, and a density of 19.3 g/cm3. Approximately how many atoms are in a spherical gold nan
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<u>Answer:</u> The number of atoms in spherical gold nano particle are 26.918\times 10^4

<u>Explanation:</u>

  • To calculate the volume of sphere, we use the equation:

V=\frac{4}{3}\pi r^3

where,

r = radius of the sphere = 10nm=10^{-6}cm    (Conversion factor:  1nm=10^{-7}cm )

Putting values in above equation, we get:

V=\frac{4}{3}\times 3.14\times (10^{-6})^3\\\\V=4.19\times 10^{-18}cm^3

  • To calculate mass of of the substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Volume of gold = 4.19\times 10^{-18}cm^3

Density of gold = 19.3g/cm^3

Putting values in above equation, we get:

19.3g/cm^3=\frac{\text{Mass of gold}}{4.19\times 10^{-18}}\\\\\text{Mass of gold}=8.0867\times 10^{-17}g

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Mass of gold = 8.8067\times 10^{-17}g

Molar mass of gold = 196.97 g/mol

Putting values in above equation, we get:

\text{Moles of gold}=\frac{8.8067\times 10^{-17}g}{196.97g/mol}=4.47\times 10^{-9}moles

  • According to mole concept:

1 mole of an element contains 6.022\time 10^{23}  number of atom

So, 4.47\times 10^{-19} moles of gold will contain = 4.47\times 10^{-19}\times 6.022\times 10^{23}=26.918\times 10^4 number of atoms.

Hence, the number of atoms in spherical gold nano particle are 26.918\times 10^4

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