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mote1985 [20]
3 years ago
6

Hi i do not have a question i just want to show u my cute doggo :)) ik everyone on here is probably stressed so hope this makes

ur day better
btw this is not my dog but if u see the first one i did that is my dog heheh

Physics
2 answers:
Arisa [49]3 years ago
5 0

Answer:

wooowwwwww

Explanation:

it's so so cuteeeeeeee

I love dogs tho:))

alekssr [168]3 years ago
3 0

Answer:

cute dog can I get brainly

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Energy in motion is _____ energy. potential scientific kinetic
Ket [755]

Answer:

kinetic energy

Explanation:

4 0
4 years ago
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Please help me with this question​
Ksju [112]

Answer:

i can not read that sorry

4 0
3 years ago
A stationary 6-kg shell explodes into three pieces. One 4.0 kg piece moves horizontally along the negative x-axis. The other two
natta225 [31]

Answer:

-15 m/s

Explanation:

The computation of the velocity of the 4.0 kg fragment is shown below:

For this question, we use the correlation of the momentum along with horizontal x axis

Given that

Weight of stationary shell = 6 kg

Other two fragments each = 1.0 kg

Angle = 60

Speed = 60 m/s

Based on the above information, the velocity = v is

1\times 60 \times cos\ 60 + 1\times 60 \times cos\ 60 - 4\ v = 0

\frac{60}{2} + \frac{60}{2} - 4\ v = 0

v = \frac{60}{4}

= -15 m/s

4 0
3 years ago
you have been called to testify as a as an expert witness in a trial involving a head-on collision Car A weighs 1515 pounds and
GrogVix [38]

Answer:

70.6 mph

Explanation:

Car A mass= 1515 lb

Car B mass=1125 lb  

Speed of car B is 46 miles/h

Distance before locking, d=19.5 ft

Coefficient of kinetic friction is 0.75

Initial momentum of car B=mv where m is mass and v is velocity in ft/s  

46 mph*1.46667=67.4666668 ft/s

Momentum_B=1125*67.4666668 ft/s

Initial momentum of car A is given by

Momentum_A=1515v_a where v_a is velocity of A

Taking East as positive and west as negative then the sum of initial momentum is

1515v_a-(1125*67.4666668 ft/s)

The common velocity is represented as v_c hence after collision, the final momentum is

Momentum_final=(m_a+m_b)v_c=(1515+1125)v_c=2640v_c

From the law of conservation of linear momentum, sum of initial and final momentum equals each other hence

1515v_a-(1125*67.4666668 ft/s)= 2640v_c

The acceleration of two cars a=-\mug=-0.75*32.17=-24.1275 ft/s^{2}

From kinematic equation

v^{2}=u^{2}+2as hence

v^{2}-u^{2}=2as

0^{2}-(v_c)^{2}=2*-24.1275*19.5

v_c=\sqrt{2*24.1275*19.5}=30.67 ft/s

Substituting the value of v_c in equation 1515v_a-(1125*67.4666668 ft/s)= 2640v_c

1515v_a-(1125*67.4666668 ft/s)= 2640*30.67

1515v_a=(1125*67.4666668 ft/s)+2640*30.67

v_a=\frac {156868.8}{1515}=103.5438 ft/s

\frac {103.5438}{1.46667}=70.59787 mph\approx 70.60 mph

3 0
3 years ago
If the heating curve is reversed, what would best describe the boiling point?
Slav-nsk [51]

Answer:

point of condensation

Explanation:

7 0
3 years ago
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