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mote1985 [20]
3 years ago
6

Hi i do not have a question i just want to show u my cute doggo :)) ik everyone on here is probably stressed so hope this makes

ur day better
btw this is not my dog but if u see the first one i did that is my dog heheh

Physics
2 answers:
Arisa [49]3 years ago
5 0

Answer:

wooowwwwww

Explanation:

it's so so cuteeeeeeee

I love dogs tho:))

alekssr [168]3 years ago
3 0

Answer:

cute dog can I get brainly

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Steam at 100°C is condensed into a 38.0 g aluminum calorimeter cup containing 280 g of water at 25.0°C. Determine the amount of
KonstantinChe [14]

Answer:

7.2g

Explanation:

From the expression of latent heat of steam, we have

Heat supplied by steam = Heat gain water + Heat gain by calorimeter

mathematically,

m_{s}c_{w} \alpha _{w} + m_{s}l=m_{w}c_{w} \alpha _{w} +m_{c}c_{c} \alpha c_{c}

L=specific latent heat of water(steam)=2268J/g

c_{w}=specific heat capacity=4.2J/gK

c_{c}=specific heat capacity of calorimeter =0.9J/gk

m_{w}=280g

m_{c}=38g

α=change in temperature

\alpha _{c}=(40-25)=15

\alpha _{w}=(40-25)=15

\alpha _{s}=(100-40)=60

Note: the temperature of the calorimeter is the temperature of it content.

From the equation, we can make m_{s} the subject of formula

m_{s}=\frac{m_{w}c_{w} \alpha +m_{c}c_{c}\alpha}{c_{w}\alpha +l}

Hence

m_{s}=\frac{(280*4.2*15) +(38*0.9*15)}{(4.2*60) +2268} \\m_{s}=\frac{18153}{2520}\\ m_{s}=7.2g

Hence the amount of steam needed is 7.2g

6 0
3 years ago
Helpppppppppppppppppppppppppppopppppppppp
harkovskaia [24]

Answer:

I think it's 2 the photo is hard to tell what they are exactly talking about.

7 0
3 years ago
The most precise measurement of the speed of light in vacuum is 299,792,458 m/s. Which of the following values would you use to
Luda [366]

Answer:

v = 3.00 x 10⁸ m/s

Explanation:

given,

speed of light in vacuum = 299,792,458 m/s

speed of light in scientific notation to three significant figures

v = 2.99792458  x  10⁸ m/s

by rounding off the speed to three significant figure.

v = 3.00 x 10⁸ m/s

On the fourth place the value is greater than 5 so, on the third place 1 will be added.

now, the speed with three significant figure comes out to be

v = 3.00 x 10⁸ m/s

3 0
3 years ago
A crucial characteristic of turbines in tidal generators is that _____.
Mila [183]
<span>The blades should turn in two directions.</span>
4 0
2 years ago
Read 2 more answers
the end of the tracks, 8.8 m lower vertically, is a horizontally situated spring with constant 5 × 105 N/m. The acceleration of
devlian [24]

Answer

Assuming the mass of the car, m = 43000 kg

initial speed u = 0

vertical distance moved, h = 8.8 m

spring constant k = 5 x  10⁵ N / m

acceleration of gravity = 9.8 m/s²

From law of conservation of energy ,

Gravitational potential energy at starting position =potential energy of the spring at maximum compression

                m g h =\dfrac{1}{2}k x^2

                x = \sqrt{\dfrac{2mgh}{k}}

                x = \sqrt{\dfrac{2\times 43000\times 9.8\times 8.8}{5\times 10^5}}

                    x = 14.83 m

If the mass of the car is equal to 43000 Kg the spring is compressed to 14.83 m

6 0
3 years ago
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