All categories

3 years ago

What is beter my cat form or demon form

Physics

2 answers:

Alexeev081 [22]3 years ago

8 0

I like the demon form!

Alexeev081 [22]3 years ago

8 0

Answer:

YeYYYyyyyyyy! dEMOn sI a hOtTiE!

You might be interested in

The contribution of Tycho Brahe was primarily his

mihalych1998 [28]

Tycho Brahe ( 1546 - 1601 ) was a Danish astronomer known for his accurate astronomical and planetary observations. Tycho tried to produce a model with the best of both Ptolemy ( earth-centered solar system ) and Copernicus ( sun-centered solar system ).
Answer: B ) observation.

3 0

3 years ago

Juliana walks 45 meters East, 45 meters south and 45 meters north. What is her resultant displacement?

katrin2010 [14]

Her resultant displacement is (45 Meters East.)

She originally walks 45 meters east, then she goes south 45 meters, then north 45 meters. The south and north placements just make her go back to where her previous placements were before them. Making her 45 meters east.

6 0

3 years ago

Which of the following atmospheric conditions are needed to create the winds?

Talja [164]

Answer:

is there suppose to be a pic?

Explanation:

5 0

3 years ago

Read 2 more answers

Vector A= 3.7 i + 1.0 j and vector B = 3.0 i + 6.5 j. What is vector (A-B).A?

kicyunya [14]

Answer:

(A - B).A = -2.91

Explanation:

First, let's define the sum and dot product of vectors.

For two vectors V = (x₁, y₁) and W = (x₂, y₂) we have:

sum (or subtraction):

V + W = (x₁, y₁) + (x₂, y₂) = (x₁ + x₂, y₁ + y₂)

dot product:

V.W = (x₁, y₁).(x₂, y₂) = x₁*x₂ + y₁*y₂

Here remember the notation:

V = x₁*i + y₁*j = (x₁, y₁)

Now let's solve our problem, we have:

A = (3.7, 1.0)

B = (3.0, 6.5)

Then:

(A - B).A = ( (3.7, 1.0) - (3.0, 6.5) ).(3.7, 1.0)

= (3.7 - 3.0, 1.0 - 6.5).(3.7, 1.0)

= (0.7, -5.5).(3.7, 1.0) = (0.7*3.7) + (-5.5)*(1.0) = -2.91

8 0

3 years ago

an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per seco

Semenov [28]

Answer:

ac = 72 m/s²

Fc = 504 N

Explanation:

We can find the centripetal acceleration of the hammer by using the following formula:

$a_c = \frac{v^2}{r}$

where,

ac = centripetal acceleration = ?

v = constant speed = 12 m/s

r = radius = 2 m

Therefore,

$a_c = \frac{(12\ m/s)^2}{2\ m}$

ac = 72 m/s²

Now, the centripetal force applied by the athlete on the hammer will be:

$F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)$

Fc = 504 N

6 0

3 years ago