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3 years ago

What is a car's acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s?

Physics

2 answers:

liberstina [14]3 years ago

8 0

the correct answer would be C. 5m/s^2

20-5 = 15

15/3 = 5

nata0808 [166]3 years ago

6 0

Answer : The acceleration of the car is, $5m/s^2$

Explanation :

By the 1st equation of motion,

$v=u+at$ ...........(1)

where,

v = final velocity = 20 m/s

u = initial velocity = 5 m/s

t = time = 3 s

a = acceleration of the car = ?

Now put all the given values in the above equation 1, we get:

$20m/s=5m/s+a\times (3s)$

$a=5m/s^2$

Therefore, the acceleration of the car is, $5m/s^2$

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A cylinder 0.170 m in diameter rotates in a lathe at 530 rpm . what is the tangential speed of the surface of the cylinder?

Ad libitum [116K]

Diameter = 0.170 meter
Circumference = 0.170 π meters

530 rpm = 530 circumferences / minute

   = (530 x 0.170 π meters) / minute

   =    283.06 meter.minute

   =    4.72 meters/second

8 0

3 years ago

4.5 billion km, the average separation between the sun and Neptune (report answer in hours). How long does it take light to trav

Liula [17]

Answer:

t = 4.17 hours

Explanation:

given,

The distance between Sun and Neptune, d = 4.5 billion Km

= 4.5 x 10⁹ Km

= 4.5 x 10¹¹ m

The velocity of light, c = 3 x 10⁸ m/s

The velocity is always equal to displacement by the time.

∴ t = d / V

= 4.5 x 10¹¹ m / 3 x 10⁸ m/s

= 15,000 s

= 4.17 h

Hence, the time taken by the light rays to reach the Neptune is, t = 4.17 h

4 0

3 years ago

Define the law of universal gravitation in your own words.

Firdavs [7]

Newton's law of universal gravitation states that a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers

7 0

3 years ago

What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a

Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

Tx= T cos 40 = T× 0.7660 N

==>T× 0.7660 = 29.4

==> T= 38.38 N

8 0

3 years ago

(URGENT) A ball rolls off a ledge. Its velocity is 7.70m/s in a horizontal direction. It falls on the floor 1.60m below the ledg

elena-s [515]

Answer:

the horizontal distance is 4.355 meters

Explanation:

The computation of the horizontal distance while travelling in the air is shown below:

Data provided in the question is as follows

Velocity = u = 7.70 m/s

H = 1.60 m

R = horizontal direction

Based on the above information

As we know that

R = u × time

where,

Time = $\sqrt{\frac{2H}{g} }$

So,

= $7.70\times \sqrt{\frac{2\times 1.60}{10} }$

= 4.355 meters

hence, the horizontal distance is 4.355 meters

6 0

3 years ago