What is a car's acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s?
2 answers:
Answer : The acceleration of the car is,
Explanation :
By the 1st equation of motion,
...........(1)
where,
v = final velocity = 20 m/s
u = initial velocity = 5 m/s
t = time = 3 s
a = acceleration of the car = ?
Now put all the given values in the above equation 1, we get:
Therefore, the acceleration of the car is,
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Answer:
x ’= 1,735 m, measured from the far left
Explanation:
For the system to be in equilibrium, the law of rotational equilibrium must be fulfilled.
Let's fix a reference system located at the point of rotation and that the anticlockwise rotations have been positive
They tell us that we have a mass (m1) on the left side and another mass (M2) on the right side,
the mass that is at the left end x = 1.2 m measured from the pivot point, the mass of the right side is at a distance x and the weight of the body that is located at the geometric center of the bar
x_{cm} = 1.2 -1
x_ {cm} = 0.2 m
Σ τ = 0
w₁ 1.2 + mg 0.2 - W₂ x = 0
x =
x =
let's calculate
x = 2.9 1.2 + 4 0.2 / 8
x = 0.535 m
measured from the pivot point
measured from the far left is
x’= 1,2 + x
x'= 1.2 + 0.535
x ’= 1,735 m