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Marrrta [24]
2 years ago
11

A^p . a^q =a) (pq)^ab) a^(p-q)c) a^(p+q)d)a^(pq)​

Mathematics
1 answer:
ivanzaharov [21]2 years ago
7 0

Answer:

a^( p + q )

Step-by-step explanation:

a^p . a^q = a^( p + q )

Note : -

This is actually a formula / identity.

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A 0.3 ml dose of a drug is injected into a patient steadily for 0.65 seconds. At the end of this time, the quantity, , of the dr
Darya [45]
Use the compound interest formula: A=P(1+i)^t.

P is the initial amount of the drug, 0.3ml.
i is - 0.0035.
t is in seconds.

You'll get:
A=0.3(1-0.0035)^t.

Sub in any value on t to find out how many ml are left t seconds after injection.

The 0.65 second injection time does not seem to be relevant as the question clearly states that the exponential decay starts AFTER the injection is completed.
4 0
3 years ago
(2x² + 3x + 2)-( x² - 4x - 1)
Scorpion4ik [409]

Answer:69

Step-by-step explanation:

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3 years ago
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Komok [63]

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7 0
2 years ago
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Y = 3/2x + 5/4 −2x + 8y = −25
Andreyy89

Answer:

<h2>x = -347 1/2</h2>

Step-by-step explanation:

When solving algebra, it is important the we follow the steps in correct order and check our answer at the end.

Step 1: Simplify by combining like terms

y = -x/2 + 5/4 + 8y = -25

Step 2: Substitute

y = -25

-25 = -x/2 + 5/4 + 8(-25)

-25 = -x/2 + 5/4 + -200

-25 = -x/2 - 198 3/4

Step 3: Answer

x = -347 1/2

Step 4: Check

y = 3/2x + 5/4 −2x + 8y = −25

-25 = 3/2(-347 1/2) + 5/4 −2(-347 1/2) + 8(-25)

-25 = -25✔️

Step 5: Verified Answer

x = -347 1/2

I'm always happy to help :)

3 0
3 years ago
I need help with this questions 2 3 p + 4 3 p – 1 3 p
erastovalidia [21]
Let's simplify step-by-step.
23
p
+
43
p
−
13
p
=
23
p
+
43
p
+
−
13
p
Combine Like Terms:
=
23
p
+
43
p
+
−
13
p
=
(
23
p
+
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p
+
−
13
p
)
=
53
p
Answer:
3 0
3 years ago
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