2 years ago

A^p . a^q =a) (pq)^ab) a^(p-q)c) a^(p+q)d)a^(pq)

Mathematics

1 answer:

ivanzaharov [21]2 years ago

7 0

Answer:

a^( p + q )

Step-by-step explanation:

a^p . a^q = a^( p + q )

Note : -

This is actually a formula / identity.

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A^p . a^q =a) (pq)^ab) a^(p-q)c) a^(p+q)d)a^(pq)​

A^p . a^q =a) (pq)^ab) a^(p-q)c) a^(p+q)d)a^(pq)