Explanation:
The Order of Reaction refers to the power dependence of the rate on the concentration of each reactant.
The overall order of reaction is the sum of the individual orders of reaction with respect to the reactants.
Rate = k [A]²[B]¹
In the rate law above, the rate is second order with respect to A and first order with respect to B. The overall order of reaction is a third order reaaction given as; 2+ 1 = 3
Whether water is frozen, in a gaseous state, or is a liquid, it is still H2O. So the chemical composition does stay the same.
Answer:
[Ne]3s2
Explanation:
ahora tenemos que mirar cada una de las configuraciones electrónicas de cada átomo de cerca antes de tomar una decisión.
considerando la configuración electrónica más externa de cada una de las especies mostradas;
para la primera configuración, ns2 np6 corresponde a un gas noble.
para la segunda configuración ns2 np3 corresponde a un elemento no metálico del grupo 5.
para la tercera configuración, ns2 corresponde a un elemento metálico del grupo 2.
para la cuarta configuración, ns2 np4 corresponde a un elemento no metálico del grupo 6
Answer:
Photosynthetic bacteria must take in <u>Carbon Dioxide</u> to live, and they release <u>Oxygen </u> . Animals must take <u>Oxygen </u> to live, and they release <u>Carbon Dioxide.</u>
Explanation:
Photosynthesis:
It is the process in which in the presence of sun light and chlorophyll by using carbon dioxide and water plants produce the oxygen and glucose.
Carbon dioxide + water + energy → glucose + oxygen
water is supplied through the roots, carbon dioxide collected through stomata and sun light is capture by chloroplast.
Chemical equation:
6H₂O + 6CO₂ + energy → C₆H₁₂O₆ + 6O₂
Photosynthetic bacteria perform same function as plants. These bacteria contain light harvesting pigments absorb carbon dioxide and release oxygen.
While animals take oxygen and release carbon dioxide to live. This respiration process is opposite to the photosynthesis.
Glucose + oxygen → carbon dioxide + water + 38ATP
Answer:
m H2(g) = 2.241 g H2(g)
Explanation:
- 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3 H2(g)
limit reagent:
∴ Mw Al = 26.982 g/mol
∴ Mw H2SO4 = 98.0785 g/mol
⇒ n Al = (20 g Al)×(mol/26.982 g) = 0.7412 mol Al
⇒ n H2SO4 = ( 115 g H2SO4 )×(mol/98.0785 g) = 1.173 mol H2SO4
⇒ n H2 = (0.7412 mol Al)×(3 mol H2/ 2 mol Al) = 1.112 mol H2
∴ Mw H2 = 2.016 g/mol
⇒ g H2 = (1.112 mol H2)×(2.016 g/mol) = 2.241 g H2
