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2 years ago

A white salt containing an unknown metal has the formula MCl and gives a lilac flame during a flame test. the salt could be

Chemistry

1 answer:

Tatiana [17]2 years ago

7 0

Answer:

Explanation:

KCl - the flame test for Potassium produces a lilac flame

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Answer:

I believe its 1,2, and 5

Explanation:

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3 years ago

Nonrenewable energy sources come out of the ground as liquids, gases,

elixir [45]

Answer:

TRUE

Explanation:

Production of Hydrocarbons from Natural Gas is as stated below:

Natural gas liquids include propane, butane, pentane, hexane, and heptane, but not methane and not always ethane, (may include it sometimes.) since these hydrocarbons need refrigeration to be liquefied.

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1 year ago

A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next fe

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Answer:

The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

As molecules heat they begin to move faster. The heat from the metal plate will make the molecules at room temperature move faster. And the room temperature makes the hot place cool, making the hot plate molecules slow down.

To visualize this, you can use this link

https://phet.colorado.edu/en/simulations/gas-properties

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2 years ago

How many moles of FeCI3 are present in 345.0 g FeCI3

Sphinxa [80]

Answer:

$\boxed {\boxed {\sf About \ 2.127 \ moles \ of \ FeCl_3}}$

Explanation:

To convert from moles to grams, the molar mass must be used.

1. Find Molar Mass

The compound is iron (III) chloride: FeCl₃

First, find the molar masses of the individual elements in the compound: iron (Fe) and chlorine (Cl).

Fe: 55.84 g/mol

Cl: 35.45 g/mol

There are 3 atoms of chlorine, denoted by the subscript after Cl. Multiply the molar mass of chlorine by 3 and add iron's molar mass.

FeCl₃: 3(35.45 g/mol)+(55.84 g/mol)=162.19 g/mol

This number tells us the grams of FeCl₃ in 1 mole.

2. Calculate Moles

Use the number as a ratio.

$\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}$

Multiply by the given number of grams, 345.0.

$345.0 \ g \ FeCl_3 *\frac{162.19 \ g \ FeCl_3}{1 \ mol \ FeCl_3}$

Flip the fraction so the grams of FeCl₃ will cancel.

$345.0 \ g \ FeCl_3 *\frac{1 \ mol \ FeCl_3}{162.19 \ g \ FeCl_3}$

$345.0 *\frac{1 \ mol \ FeCl_3}{162.19 }$

$\frac{345.0 \ mol \ FeCl_3}{162.19 }$

Divide.

$2.12713484 \ mol \ FeCl_3$

3. Round

The original measurement of grams, 345.0, has 4 significant figures. We must round our answer to 4 sig figs.

For the answer we calculated, that is the thousandth place.

The 1 in the ten thousandth place tells us to leave the 7 in the thousandth place.

$\approx 2.127 \ mol \ FeCl_3$

There are about 2.127 moles of iron (III) chloride in 345.0 grams.

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2 years ago

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