WILL GIVE BRAINLIEST

A child of mass 47 kg sits on the edge of a merry-go-round with radius 1.3 m and moment of inertia 56.3953 kg m2 . The merrygo-r

lakkis [162]

Answer:

$F=156.416\ N$ the child have to exert this much amount of force radially to stay on the wheel.

Explanation:

Given:

mass of the child, $m=47\ kg$

radius of the merry-go round wheel, $r=1.3\ m$

moment of inertia of the wheel, $I=56.3953\ kg.m^2$

angular velocity of the wheel, $\omega=1.6\ rad.s^{-1}$

Since the child is sitting on the edge of the rotating wheel the child will feel and outward throwing force called centrifugal force.

Centrifugal force is mathematically given as:

$F=m.r.\omega^2$

$F=47\times 1.3\times 1.6^2$

$F=156.416\ N$ the child have to exert this much amount of force radially to stay on the wheel.

4 0

3 years ago

A(n) ________ is a thick accumulation of sediments and small tectonic blocks formed of material scraped off subducting oceanic l

diamong [38]

C) accretionary-wedge complex.

Explanation:

The accretionary wedge complex is a thick accumulation of sediments and small tectonic blocks formed from materials scraped off subducting oceanic lithosphere at a convergent margin.

Space between the subducting plate and the less dense plate gets filled by sediments scraped off the subducting plate and this forms a wedge like sediment called the accretionary wedge.

The accretionary wedge is invariably made up of materials found on the ocean floor.
Under extreme conditions, some parts of wedge transforms into metamorphic rocks.
The wedge is made up of: pelagic sediments, ocean floor basalts e.t.c

Learn more:

Sedimentary rocks brainly.com/question/9131992

#learnwithBrainly

3 0

3 years ago

Which optical device can focus light to a point through reflection?

frosja888 [35]

Answer:

A

Explanation:

did the quiz

7 0

2 years ago

A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo

BARSIC [14]

We are given that,

$\frac{dx}{dt} = 4ft/s$

We need to find $\frac{d\theta}{dt}$ when $x=8ft$

The equation that relates x and $\theta$ can be written as,

$\frac{x}{6} tan\theta$

$x = 6tan\theta$

Differentiating each side with respect to t, we get,

$\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}$

$\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}$

$\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}$

Replacing the value of the velocity

$\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2$

$\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta$

The value of $cos \theta$ could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to

$cos\theta = \frac{6}{10}$

$\frac{d\theta}{dt} = \frac{8}{3} (\frac{6}{10})^2$

$\frac{d\theta}{dt} = \frac{24}{25}$

Search light is rotating at a rate of 0.96rad/s

4 0

3 years ago

In preparation for the final exam, our astronomy study group has reconvened to discuss Mercury's unique orbital properties. They

grigory [225]

Answer:

The only incorrect statement is from student B

Explanation:

The planet mercury has a period of revolution of 58.7 Earth days and a rotation period around the sun of 87 days 23 ha, approximately 88 Earth days.

Let's examine student claims using these rotation periods

Student A. The time for 4 turns around the sun is

t = 4 88

t = 352 / 58.7 Earth days

In this time I make as many rotations on itself each one with a time to = 58.7 Earth days

#_rotaciones = t / to

#_rotations = 352 / 58.7

#_rotations = 6

therefore this statement is TRUE

student B. the planet rotates 6 times around the Sun

t = 6 88

t = 528 s

The number of rotations on itself is

#_rotaciones = t / to

#_rotations = 528 / 58.7

#_rotations = 9

False, turn 9 times

Student C. 8 turns around the sun

t = 8 88

t = 704 days

the number of turns on itself is

#_rotaciones = t / to

#_rotations = 704 / 58.7

#_rotations = 12

True

The only incorrect statement is from student B

6 0

2 years ago