Answer is: the approximate freezing point of a 0.10 m NaCl solution is -2x°C.
V<span>an't
Hoff factor (i) for NaCl solution is approximately 2.
</span>Van't Hoff factor (i) for glucose solution is 1.<span>
Change in freezing point from pure solvent to
solution: ΔT = i · Kf · m.
Kf - molal freezing-point depression constant for water is 1,86°C/m.
m - molality, moles of solute per
kilogram of solvent.
</span>Kf and molality for this two solutions are the same, but Van't Hoff factor for sodium chloride is twice bigger, so freezing point is twice bigger.
The reducing agent will itself be oxidized.
The oxidation number of carbon goes form 0 to +2. Therefore, it is the reducing agent.
13111 is already an integer (whole number). It also can be expressed as 1 ton or 13111000g.
Answer:742 torr= approximately 0.976 atm
Explanation:
Since we know that one atm= 760 torr, we can compute the following calculation:
(742 torr/1)*(1atm/760torr)=0.976316 atm
Remember sig figs (3) to round it to 0.976 atm
*
=0.976316=0.976 atm
(torr cancels out and we're left with atm)
Hope this helps :)
