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tatuchka [14]
3 years ago
6

Question 3 (1 point)

Mathematics
2 answers:
Eva8 [605]3 years ago
6 0
Fixed expense because it is a monthly payment
alexandr402 [8]3 years ago
6 0
The answer is A) fixed expense
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4 1/3 divided by 2 1/3
kobusy [5.1K]
4\frac{1}{3} = \frac{13}{3}\\2\frac{1}{3} =\frac{5}{3}\\\\\frac{13}{3}\div\frac{5}{3} = \frac{13}{3} \times\frac{3}{5} = \frac{13}{5}
4 0
3 years ago
What two ratios are equivalent to 5:9
guapka [62]
There is infinitely many ratios which are equivalent to 5:9. As we know always we can write divide as fraction, so \frac{5}{9}. We can multiply nominator and denominator by the any number (but the same) and get another numbers but ratio will be the same, so equivalent.
For example
10:18,
15:27 
7 0
3 years ago
Read 2 more answers
Need help with question 11 and 12
qaws [65]

Answer:

  11.  your choices are correct

  12.  132°

Step-by-step explanation:

11. The given equations can be (re)written to slope-intercept form. Only those lines with a slope of 2 will be parallel to the given line.

  A: y = 2x -8 . . . . . slope = 2, an answer

  B: y = -2x +1 . . . . . slope = -2, not an answer

  C: y = -2x +7 . . . . .slope = -2, not an answer

  D: y = 2x +2 . . . . . slope = 2, an answer

  E: y = -2x -9 . . . . . slope = -2, not an answer

__

12. The marked angles are supplementary, so ...

  (3x -6)° +(x +2)° = 180°

  4x -4 = 180 . . . . . . . . . . . divide by °, collect terms

  x -1 = 45 . . . . . . . divide by 4

  x = 46 . . . . . . . . . add 1

Now, we can find the angle of interest.

∠PQR = (3x -6)° = (3·46 -6)°

∠PQR = 132°

4 0
3 years ago
1 3 fourth +1half+1 fourth+ 1 half
Leona [35]
The answer is 2
------------------------
6 0
3 years ago
Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
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