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Mazyrski [523]
3 years ago
6

Which of the following is NOT a good technique for managing used oil? A) Have specific, labeled catch pans available for technic

ians who are collecting oil B) Spills in your shop and any releases on pavement or outside should be poured down a drain C) Do not use oil containers for antifreeze or other non-similar fluids D) Be prepared for oil spills with the proper absorbents
Chemistry
1 answer:
slava [35]3 years ago
8 0

The answer is: B) Spills in your shop and any releases on pavement or outside should be poured down a drain.

Pouring used oil down a drain can cause damege to environment.

Oil is nonpolar substance and does not dissolve in the water (polar molecule), used oil remain existent in the drain and sewer or in the environment.

Small spills create a cumulative effect with  significant impact on the  environment.

Untended spills inside  a shop can spread to an inside  drain connected to the storm  sewer system and cause floods.

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A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at
Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

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Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

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R = 8.314J/molK

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So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

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