If they are supplementary then 3x + 17x = 180
20x = 180
x = 9
m<GHI = 27 degrees
m < LMN = 153 degrees
Answer:
StartFraction negative 1 Over k cubed EndFraction
Step-by-step explanation:
3k / (k + 1) × (k²- 1) / 3k³
= 3k(k² - 1) / (k + 1)(3k³)
= 3k³ - 3k / 3k⁴ + 3k³
= -3k / 3k⁴
= -1/k³
StartFraction k + 1 Over k squared EndFraction
(k + 1) / k²
StartFraction k minus 1 Over k squared EndFraction
(k - 1)/k²
StartFraction negative 1 Over k cubed EndFraction
= -1/k³
StartFraction 1 Over k EndFraction
= 1/k
Answer:
C
Step-by-step explanation:
A major arc is an arc that is greater than 180 degrees.
A minor arc is an arc less than 180 degrees.
An acute angle is an angle less than 90 degrees.
A central angle is the angle created in the center of a circle with 2 sides being the radius.
<em>Thus, we can see in the figure that we are talking about the angle so we can eliminate major arc and minor arc.</em>
<em>Now, we clearly see that the angle is greater than 90 degree so it cannot be acute angle.</em>
<em />
The correct answer is central angle as it goes with the definition.
Answer:
m>7 = 142°
Step-by-step explanation:
m>6 = 38°
180° - 38° = 142°
m>7 = 142°
The area between the two functions is 0
<h3>How to determine the area?</h3>
The functions are given as:
f₁(x)= 1
f₂(x) = |x - 2|
x ∈ [0, 4]
The area between the functions is
A = ∫[f₂(x) - f₁(x) ] dx
The above integral becomes
A = ∫|x - 2| - 1 dx (0 to 4)
When the above is integrated, we have:
A = [(|x - 2|(x - 2))/2 - x] (0 to 4)
Expand the above integral
A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]
This gives
A = [2 - 4] - [-2- 0]
Evaluate the expression
A = 0
Hence, the area between the two functions is 0
Read more about areas at:
brainly.com/question/14115342
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