Ask question

Ask question

All categories

erastovalidia [21]

2 years ago

12

If a calcium supplement claims to have 200 mg of calcium per pill - how much mass if each pill if the supplement is a calcium su

lfate compound?

1 answer:

arlik [135]2 years ago

7 0

Answer: mmmmmmmmmmmmmmmmmmmmmmmmmmmm

Explanation:

mmmmmmmmmmmmmm

You might be interested in

This graph illustrates that, under conditions of constant pressure, as the temperature of liquid water increases, its volume ___

Lunna [17]

it varies.........................

8 0

2 years ago

Water is amphoteric. If it reacts with a compound that is a stronger acid than itself, water acts as a

kirza4 [7]

Answer:

Water acts as a base in the presence of a strong acid

Explanation:

Water,being an amphoteric compound, can act both as an acid and as a base.

In the presence of an acid , water acts as a base but in the presence of a base, water acts as an acid.

5 0

2 years ago

To the nearest 0.5 mL, what is<br> the water volume in the<br> graduated cylinder?<br> mL?

AnnZ [28]

Answer:

14cm^3

Explanation:

6 0

2 years ago

Which of the following compounds will not produce O2 gas when it decomposes? (2 points)

Umnica [9.8K]

LiOH is the right answer.

6 0

2 years ago

A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg

Brut [27]

Answer: $1.0\times 10^2g$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

$K_f$ = freezing point constant = $3.96^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}$

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

$7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}$

$x=1.0\times 10^2g$

Thus $1.0\times 10^2g$ urea was dissolved.

8 0

3 years ago