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solong [7]
3 years ago
13

Particles of clay and silt eroded and deposited by the wind are called

Chemistry
2 answers:
shtirl [24]3 years ago
8 0

Answer:

They are called  "loess".

Explanation:

The loess (German word from Switzerland), are sedimentary clay deposits of wind origin. It is formed by silt deposits originated by the deposition of microscopic particles, which are transported by dust storms. They are yellowish. They are formed mainly by silicates, calcium carbonate and minerals from the clay group. It constitutes a very fertile and deep soil. The silt and clay are only visible through the microscope.

Have a nice day!

Ivanshal [37]3 years ago
4 0
The correct answer to your question would be B) Loess, or <span>Aeolian deposits , reasoning to your question is because, loess is a german word but in english means loss or loose. So given that clay and small particles that are not combined together are loose particles. moves freely. Hope this helps you out.

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I need help with these questions work would be very much appreciated
kicyunya [14]
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8 0
3 years ago
If the ph of a solution is decreased from ph 8 to ph 6 it means that the
saw5 [17]

Explanation:

Relation between pH and concentration of hydrogen ions is as follows.

                  pH = -log [H^{+}]

So, it means that an increase in the value of pH will show that there occurs a decrease in concentration of hydrogen ions.

Therefore, the solution becomes basic in nature.

On the other hand, a decrease in the value of pH will show that there occurs an increase in the concentration of hydrogen ions.

Therefore, the solution becomes more acidic in nature.

Hence, if the pH of a solution is decreased from pH 8 to pH 6 it means that the concentration of hydrogen ions has increased in the solution.

5 0
3 years ago
Read 2 more answers
Convert the composition of the following alloy from atom percent to weight percent (a) 44.9 at% of silver, (b) 46.3 at% of gold,
vesna_86 [32]

Answer:

Mass percentage of gold : 33.35%

Mass percentage of silver: 62.80%

Mass percentage of copper : 3.85%

Explanation:

N=n\times N_A

Where : N = Number of atoms

n = moles

N_A=6.022\times 10^{23} = Avogadro number

Let the total atoms present in the alloy be 100.

Atom percentage of silver = 44.9%

Atoms of of silver = 44.9% of 100 atoms = 44.9

Atomic weight of silver = 107.87 g/mol

Mass of 44.9 silver atoms = 107.87 g/mol ×  44.9 = 4,843.363 g/mol

Atom percentage of gold= 46.3%

Atoms of of gold = 46.3% of 100 atoms = 46.3

Atomic weight of gold = 196.97 g/mol

Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol

Atom percentage of copper = 8.8 %

Atoms of of copper = 8.8% of 100 atoms = 8.8

Atomic weight of copper = 63.55 g/mol

Mass of 44.9 copper atoms = 63.55 g/mol ×  8.8 = 559.24 g/mol

Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol

Mass percentage of gold :

\frac{4,843.363 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=33.35 \%

Mass percentage of silver:

\frac{9,119.711 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=62.80\%

Mass percentage of copper :

\frac{559.24 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=3.85\%

7 0
3 years ago
26 g of zinc combines with 12.8 g of sulfur. What is the empirical formula of zinc sulfide?
Alisiya [41]
Moles of Zn: 26 / 65 = 0.4
Moles of S: 12.8 / 32 = 0.4

Molar ratio of Zn : S = 1 : 1
Empircal formula: ZnS

The answer is C
7 0
3 years ago
Which is a nonmetal that becomes isoelectronic with argon<br> when it forms its most common ion?
mrs_skeptik [129]

Answer:sulfur

Explanation:

6 0
3 years ago
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