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Lesechka [4]
2 years ago
13

Sketch the graph of y = 4 x squared + 32 x + 15 using your graphing calculator. What are the x-intercepts of this graph? a. (-5,

0) and (3.5, 0) c. There are no y-intercepts b. (-2.5, 0) and (-2, 0) d. (-0.5, 0) and (-7.5, 0) Please select the best answer from the choices provided A B C D
Chemistry
2 answers:
quester [9]2 years ago
8 0

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    4*x^2-32*x-(-15)=0

Explanation:

tensa zangetsu [6.8K]2 years ago
7 0

Answer: d.) x= -7.5 x= -0.5

Explanation: correct on edge 2021

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Explanation:

May the gods ever be in your favor.

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Water is a great solvent. For example, it causes ionic compounds like sodium chloride (table salt) to dissociate. One of these r
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A polar molecule has both a partial positive and a partial negative. Since NaCl (sodium chloride) is made out of Na+ and Cl- ions, the positive and negative parts of the water will pull on these ions individually since positive attracts negative and negative attracts positive. This magnetic force causes the Na+ and the Cl- ions to be pulled apart.

Explanation:

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What did Thomson’s model of the atom include that Dalton’s model did not have?
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Thomson's model included Protons and Electrons. His model is referred to as 'Plum Pudding' because of it.
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2 years ago
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How many grams of CO2 are in 2.1 mol of the compound? a) 21.0g c) 66.0g
Lilit [14]
1 mole CO2 = 44.0096 grams CO2


<span>2.1 mol CO2 x (44.0096 grams CO2/1 mole CO2) = 92.4 grams CO2</span>
8 0
3 years ago
A 3.4 g sample of an unknown monoprotic organic acid composed of C,H, and O is burned in air to produce 8.58 grams of carbon dio
Pavlova-9 [17]

Answer:

C_7H_6O_2

Explanation:

Hello there!

In this case, we can divide the problem in three stages: (1) determine the empirical formula with the combustion analysis, (2) compute the molar mass of acid via the moles of the acid in the neutralization and (3) determine the molecular formula.

(1) In this case, since 8.58 g of carbon dioxide are released, we can first compute the moles of carbon in the compound:

n_C=8.58gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2}=0.195molC

And the moles of hydrogen due to the produced 1.50 grams of water:

n_H=1.50gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O}  =0.166molH

Next, to compute the mass and moles of oxygen, we need to use the initial 3.4 g of the acid:

m_O=3.4g-0.195molC*\frac{12.01gC}{1molC}-0.166molH*\frac{1.01gH}{1molH} =0.89gO\\\\n_O=0.89gO*\frac{1molO}{16.0gO}=0.0556molO

Thus, the subscripts in the empirical formula are:

C=\frac{0.195}{0.0556}=3.5 \\\\H=\frac{0.166}{0.0556}=3\\\\O=\frac{0.0556}{0.0556}=1\\\\C_7H_6O_2

As they cannot be fractions.

(2) In this case, since the acid is monoprotic, we can compute the moles by multiplying the concentration and volume of KOH:

n_{KOH}=0.279L*0.1mol/L\\\\n_{KOH}=0.0279mol

Which are equal to the moles of the acid:

n_{acid}=0.0279mol

And the molar mass:

MM_{acid}=\frac{3.4g}{0.0279mol} =121.86g/mol

(3) Finally, since the molar mass of the empirical formula is:

7*12.01 + 6*1.01 + 2*16.00 = 122.13 g/mol

Thus, since the ratio of molar masses is 122.86/122.13 = 1, we infer that the empirical formula equals the molecular one:

C_7H_6O_2

Best regards!

8 0
3 years ago
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