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3 years ago

Does benzene have any isomers?

Chemistry

2 answers:

bonufazy [111]3 years ago

4 0

Answer:

<h3>Yeah, Benzene have isomers.</h3>

pychu [463]3 years ago

4 0

Answer:

no, benzene is not having any isomers.

Explanation:

please mark me as brainliest

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Which of these structures is found in all types of plant and animal cells

liq [111]

Answer:

Hi, There!

which of these structures is found in all types of plant and animal cells

Cell membrane is found in both animal and plant cells.

Nucleus is found in both animal and plant cells.

Cytoplasm is found in both animal and plant cells.

Mitochondria is found in both animal and plant cells.

Endoplasmic reticulum is found in both animal and plant cells.

Golgi apparatus is found in both animal and plant cells.

Lysosomes is found in both animal and plant cells.

$~Hope ~ this ~ Helps~$

5 0

3 years ago

Is this experiment okay for this question???? If not, what would a good one be?

Fed [463]

Yes that would be ok, explain how it works though.

6 0

4 years ago

Imagine a drop of water in oil. If you add surfactant, explain how the surfactant molecules organize themselves around the water

Oduvanchick [21]

If you add a surfactant in water-oil mixture, surfactant molecules would form micelles wherein the hydrophobic end of the surfactant faces inside the micelle while the hydrophilic end faces the water molecules. Inside these micelles oil particles are attached.

4 0

3 years ago

Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

anygoal [31]

Answer : The enthalpy of the given reaction will be, -1048.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The main reaction is:

$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$