Ask question

Ask question

All categories

3 years ago

9

14. What is a major disadvantage of using solar power?

2 answers:

sleet_krkn [62]3 years ago

8 0

I believe that number 27 is A

oee [108]3 years ago

6 0

14. D because all the other answers dont make cents

11. B Becuz the powerplants need to have waste

27. A Cuz reasons

You might be interested in

A piston contains 0.39L of air at 1.0 atm. If the pressure on the piston is increased to 5.6 atm, what is the new volume?

bazaltina [42]

The new volume : 0.07 L

<h3>Further explanation</h3>

Boyle's Law

At a constant temperature, the gas volume is inversely proportional to the pressure applied

$\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

P₁=1 atm

V₁=0.39 L

P₂=5.6 atm

$\tt V_2=\dfrac{P_1.V_1}{P_2}\\\\V_2=\dfrac{1\times 0.39}{5.6}\\\\v_2=\boxed{\bold{0.07~L}}$

3 0

3 years ago

This is science not chemistry

snow_lady [41]

That is actually physics because it talks about motion.

7 0

2 years ago

Electrolysis is an endothermic process when an electric current is passed through water and separates it into hydrogen and oxyge

azamat

Answer:

IM SORRY I NEED THIS ONE

Explanation:

pls dont report

3 0

3 years ago

A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin

lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, $3.0\times 10^1g$

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of iron metal = $0.45J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of iron metal = 32.3 g

$m_2$ = mass of water = ?

$T_f$ = final temperature of mixture = $59.2^oC$

$T_1$ = initial temperature of iron metal = $21.9^oC$

$T_2$ = initial temperature of water = $63.5^oC$

Now put all the given values in the above formula, we get

$32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC$

$m_2=30.16g\approx 3.0\times 10^1g$

Therefore, the mass of the water in two significant figures is, $3.0\times 10^1g$

3 0

3 years ago

One mole of aluminum atoms has a mass of 27 grams. How many grams are in 9.0 moles of aluminum?

gizmo_the_mogwai [7]

27*9=243 if one mole is equal to 27 grams times that by 9

6 0

2 years ago