Answer:
0.196 M
Explanation:
First, we have to calculate the moles of sodium hydroxide.
moles = mass / molar mass
moles = 3.9280 g / (39.997 g/mol) = 0.098207 mol
It is important to realize that even though 300 mL is the volume of water firstly added to dissolve the hydroxide, the flask is then filled to the mark, meaning that the volume of the solution is 500 mL = 0.500 L.
The molar concentration of sodium hydroxide is:
The concentration is an intensive property, that is, it does not depend on the amount of matter. As a consequence, the concentration of the 50 mL of solution in the buret is the same as the concentration in the flask.
Answer: The equilibrium constant, 
, for the reaction is 0.061.
Explanation:
Initial concentration of 
= 
Equilibrium concentration of = 
The given balanced equilibrium reaction is,
Initial conc. 0.039 M 0 M 0 M
At eqm. conc. (0.039-x) M (x) M (x) M
Given : (0.039-x) = 0.012
x = 0.027
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCl_2%5D%5Ctimes%20%5BPCl_3%5D%7D%7B%5BPCl_5%5D%7D)
Now put all the given values in this expression, we get :
The equilibrium constant, , for the reaction is 0.061.
Molar mass Argon ( Ar ) = 39.95 g/mol
39.95 g ---------------- 6.02 x 10²³ atoms
0.377 g ---------------- ( atoms Ar )
( atoms Ar ) = 0.377 x ( 6.02 x 10²³ ) / 39.95
( atoms Ar ) = 2.26954 x 10²³ / 39.95
= 5.68 x 10²¹ atoms Ar
hope this helps!
Why can’t y’all do more points then 5? why can’t it be like 20-10
Answer:
copper metal is a product of the cell reaction.
Explanation:
In writing the line notation of a cell reaction, we ought to recall that the anode is placed at the left hand side of the notation while the cathode is placed at the right hand side of the notation.
If we look at the line notation shown in the question, we will realize that the Cu2+ (aq) | Cu(s) half cell is the cathode and that copper metal is the product of the reaction as shown by the notation.
