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Grace [21]
3 years ago
3

156 g C12H22O11 (sucrose) is dissolved into 4.0 L of solution. What is the molar concentration of the solution? Report your answ

er with the correct number of significant figures.
Chemistry
1 answer:
saveliy_v [14]3 years ago
3 0

Answer:

The molar concentration is 0.114 M (≈0.11 M)

Explanation:

Step 1: Data given

Mass of sucrose = 156 grams

Molar mass of sucrose = 342.3 g/mol

Volume = 4.0 L

Step 2: Calculate moles sucrose

Moles sucrose = mass sucrose / molar mass sucrose

Moles sucrose = 156 grams / 342.3 g/mol

Moles sucrose = 0.456 moles

Step 3: Calculate molar concentration of the solution

Concentration of solution = moles sucrose / volume

Concentration of solution = 0.456 moles / 4.0 L

Concentration of solution = 0.114 M

The molar concentration is 0.114 M (≈0.11 M)

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A chemist must prepare of hydrochloric acid solution with a pH of at . He will do this in three steps: Fill a volumetric flask a
Eva8 [605]

Answer:

1.7 mL

Explanation:

<em>A chemist must prepare 550.0 mL of hydrochloric acid solution with a pH of 1.60 at 25 °C. He will do this in three steps: Fill a 550.0 mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (8.0 M) stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.</em>

Step 1: Calculate [H⁺] in the dilute solution

We will use the following expresion.

pH = -log [H⁺]

[H⁺] = antilog - pH = antilog -1.60 = 0.0251 M

Since HCl is a strong monoprotic acid, the concentration of HCl in the dilute solution is 0.0251 M.

Step 2: Calculate the volume of the concentrated HCl solution

We want to prepare 550.0 mL of a 0.0251 M HCl solution. We can calculate the volume of the 8.0 M solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 0.0251 M × 550.0 mL/8.0 M = 1.7 mL

3 0
3 years ago
The atom in a sample of an element must contain nuclei with the same number of?
slava [35]
Hey there! 

Answer: Protons 

The atom in a sample of an element must contain nuclei with the same number of protons. If the protons change in number, then the element will modify as well. 

Thank you!
7 0
3 years ago
If you accidentally lost some sand when you decanted tyhe NaCl, how would the % salt calculation be affected?
skad [1K]

Answer:

Unchanged.

Explanation:

Hello,

In this case, for the experiment you performed, as you previously removed the sodium chloride, its % salt calculation will not be affected by the lost of the sand. It is important to remember that such experiments must be performed carefully as the committed error is a high-impact factor regarding to the experiment's performance. It is important for you to remember that to separate the sodium chloride, it earlier dissolution in water allowed to be dissolved leveraging the insolubility of sand in water, thus, it was decanted easily.

Best regards.

5 0
4 years ago
When a sex cell, divides what is the result
nataly862011 [7]

The cell divides to get 2 new cells. If you may have learned, sex cells can only divide four times. in a female egg cell, only one cell out of those can make a kid. In a male, all four cells are ready to make babies.

Hope this helps :)

5 0
4 years ago
Read 2 more answers
Can someone actually help me with this?
Tpy6a [65]

Answer:

p = 43, n = 57, e = 40

Explanation:

Z is the number of protons. The number of neutrons, subtract Z from the isotope number (100). To begin with, protons and electrons are equal in an atom, but this atom lost three, so subtract 3 from Z.

Z= # of protons = 43

100 - 43 = 57 neutrons

43 - 3 = 40 electrons.

8 0
4 years ago
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