A farmer has concerns about the nitrogen levels in her soils. What can she do to ensure that the nitrogen bacteria are replenish
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Answer:
Following are the answer to this question:
Explanation:
The value of pH solution is =5.17 So, the p^{OH}:
=14-56.17
=8.823
The volume of the = 40.00 ml
convert into the liter= 0.040L
The value of the concentrated =0.10 M
The volume of the = 50.00 ml
convert into the liter= 0.050L
The value of concentrated = 0.10 M
The volume of the = 30 ml
convert into the liter= 0.030L
The value of concentrated =0.05 M
Calculating total volume=(0.40+0.050+0.030)
=0.120 L
calculating the new concentrated value of =
calculating the new concentrated value of =
calculating the new concentrated value of
when 1 mol
produced 2 mols
so, 0.0125 in
produced:
create the ICE table:
I (m) 0.033(m) 0.025 0.04166
C -0.025 -0.025 + 0.025
E 8.3\times 10^{-3} 0 0.0667
now calculating pH:
when ph= 8.83:
Formal Charge is calculated as, Lewis structure is attached below,
Formal Charge = [# of valence electrons] - [electrons in lone pairs + 1/2 the number of bonding electrons]
# of valence electrons of Cl = 7
electrons in lone pairs = 4
number of bonding electrons = 6
Formal Charge = [7] - [4 + 6/2]
Formal Charge = [7] - [4 + 3]
Formal Charge = [7] - [7]
Formal Charge = 0
Result:
Formal charge on Cl in ClF₃ is zero.
Formal Charge = [# of valence electrons] - [electrons in lone pairs + 1/2 the number of bonding electrons]
# of valence electrons of Cl = 7
electrons in lone pairs = 4
number of bonding electrons = 6
Formal Charge = [7] - [4 + 6/2]
Formal Charge = [7] - [4 + 3]
Formal Charge = [7] - [7]
Formal Charge = 0
Result:
Formal charge on Cl in ClF₃ is zero.