Answer:
We will split the trapezoid into right angle triangle and rectangle
Traingle with base 3cm and height 10 - 6 = 4cm
Area of traingle
= 
Area of rectangle with sides 6cm and 3cm
=
Therefore, area of the trapezoid
=
Area of the semi circle with radius 3/2 = 1.5cm
= 

Answer:
b+3a
Step-by-step explanation:
MN=AN+AM
AN=0.5*AB
AB=OA+OB=4a+2b
AN=2a+b
AM=OA-OM=4a-3a=a
MN=2a+b+a=3a+b
X³ = 125/27
Cube root both sides to isolate the variable:
∛x³ = ∛(125/27)
x = ∛(125/27)
∛125 = 5, ∛27 = 3
x = 5/3
cuatro no? porque osea tiene q
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r =
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!