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Amiraneli [1.4K]
2 years ago
12

A school dedicated 50% of the courtyard area for students to start a garden the students went to know how much of the 632- squar

e foot space they will be able to use.

Mathematics
1 answer:
Lilit [14]2 years ago
6 0

Answer:

316

Step-by-step explanation:

50% is just half

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PLEASE NO LINKS I LOST SO MANY POINTS
Ann [662]

Answer:

We will split the trapezoid into right angle triangle and rectangle

Traingle with base 3cm and height 10 - 6 = 4cm

Area of traingle

       = \frac{1}{2}*base *height = \frac{1}{2} * 3 * 4 = 6cm^{2}

Area of rectangle with sides 6cm and 3cm

       =6 * 3 = 18cm^{2}

Therefore, area of the trapezoid

       = 6+18 = 24cm^{2}

Area of the semi circle with radius 3/2 = 1.5cm

        = \frac{1}{2}\pi r^{2}  = \frac{1*\pi *1.5*1.5}{2} = 1.125\pi cm^{2}

Total area = 24 + 1.125\pi =27.53cm^{2}

8 0
3 years ago
Could anyone please help?​
natima [27]

Answer:

b+3a

Step-by-step explanation:

MN=AN+AM

AN=0.5*AB

AB=OA+OB=4a+2b

AN=2a+b

AM=OA-OM=4a-3a=a

MN=2a+b+a=3a+b

3 0
3 years ago
Read 2 more answers
X^3 = 125 over 27 CAN I PLEASE GET HELP
Zinaida [17]
X³ = 125/27

Cube root both sides to isolate the variable:

∛x³ = ∛(125/27)

x = ∛(125/27)

∛125 = 5, ∛27 = 3

x = 5/3 
5 0
3 years ago
2+5+2) = 6(+2)
Sergio039 [100]

cuatro no? porque osea tiene q

5 0
3 years ago
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
2 years ago
Read 2 more answers
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